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Dennis_Churaev [7]
3 years ago
6

Given a circle with measures of (C, d, and r) and a circle with measures of (C', d', and r'), what is C' if

Mathematics
1 answer:
Anestetic [448]3 years ago
5 0

Answer:

The answer can be calculated by doing the following steps;

Step-by-step explanation:

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emmasim [6.3K]
Answer:\frac{2}{5}+\frac{1}{3}=\frac{6}{15}+\frac{5}{15}=\frac{11}{15}Explanation:

The given addition exercise is:

\frac{2}{5}+\frac{1}{3}

The LCM of the denominator (5 and 3) = 15

Multiply 2/5 by 3/3

\frac{2}{5}=\frac{2\times3}{5\times3}=\frac{6}{15}

Multiply 1/3 by 5/5

\frac{1}{3}=\frac{1\times5}{3\times5}=\frac{5}{15}

The addition becomes

\frac{6}{15}+\frac{5}{15}=\frac{11}{15}

Therefore, we can fill in the vacant boxes as shown below:

\frac{2}{5}+\frac{1}{3}=\frac{6}{15}+\frac{5}{15}=\frac{11}{15}

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Answer:

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Step-by-step explanation:

2y-3[3-4(y-5)+2(1-3y)]

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Answer:


Step-by-step explanation:

38 computers times $345 per computer

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