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Dennis_Churaev [7]
3 years ago
6

Given a circle with measures of (C, d, and r) and a circle with measures of (C', d', and r'), what is C' if

Mathematics
1 answer:
Anestetic [448]3 years ago
5 0

Answer:

The answer can be calculated by doing the following steps;

Step-by-step explanation:

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Which expressions are equivalent to 7 (negative three-fourths x minus 3)? Select two options.
polet [3.4K]

<em><u>The equivalent expressions are:</u></em>

7(-\frac{3}{4}x - 3) = (7 \times \frac{-3}{4}x) + (7 \times -3)\\\\7(-\frac{3}{4}x - 3) = \frac{-21x}{4} - 21

<em><u>Solution:</u></em>

<em><u>Given expression is:</u></em>

7(-\frac{3}{4}x - 3)

We have to find the equivalent expressions

By distributive property,

a(b + c) = ab + ac

Therefore,

7(-\frac{3}{4}x - 3) = (7 \times \frac{-3}{4}x) + (7 \times -3)\\\\7(-\frac{3}{4}x - 3) = \frac{-21x}{4} - 21

Thus equivalent expressions are found

7 0
3 years ago
Read 2 more answers
If area of a circle is 49/64 pie cm square,then find the circumference of the circle?​
tresset_1 [31]

Answer:

7/4 * pi

Step-by-step explanation:

Area of circle = pi * r^2

Find radius:

pi * 49/64 = pi * r^2

49/64 = r^2

7/8= r

Circumference of circle = 2pi * r

2 * pi * (7/8) = 7/4 * pi

Assuming that the answer is in terms of pi as the question is in terms of pi

8 0
2 years ago
Read 2 more answers
Evaluate the function fx = 4 * 7^t for x= -1 and x=2
Alex73 [517]
Well what i think you're asking here...I apologie if I'm wrong but what I did was 

f(-1) = 4 * 7^t = 4/7 

and 

f(2) = 4 * 7^t = 196.

Is this what you wanted if not I can...try another way. 
6 0
3 years ago
25 POINTS AND BRAINLIEST PLEASE HELP ASAP
dexar [7]
M is a midpoint of BC so:

M=\left(\dfrac{\boxed{2}\boxed{a}+a}{\boxed{2}},\dfrac{\boxed{0}+b}{2}\right)=\left(\dfrac{\boxed{3}\boxed{a}}{\boxed{2}},\dfrac{\boxed{b}}{\boxed{2}}\right)

Length of MA:

MA=\sqrt{\left(\dfrac{\boxed{3}a}{2}\boxed{-}\boxed{0}\right)^2+\left(\dfrac{\boxed{b}}{2}\boxed{-}\boxed{0}\right)^2}=\\\\\\=&#10;\sqrt{\left(\dfrac{\boxed{3}a}{\boxed{2}}\right)^2+\left(\dfrac{b}{2}\right)^2}=\sqrt{\dfrac{\boxed{9}a^2}{\boxed{4}}+\dfrac{\boxed{b}^2}{\boxed{4}}}

Length of NB:

NB=\sqrt{\left(\dfrac{a}{2}\boxed{-}\boxed{2}a\right)^2+\left(\dfrac{b}{2}\boxed{-}\boxed{0}\right)^2}=\\\\\\=\sqrt{\left(\dfrac{a}{2}\boxed{-}\dfrac{\boxed{4}\boxed{a}}{2}\right)^2+\left(\dfrac{b}{2}-\boxed{0}\right)^2}=\\\\\\&#10;\sqrt{\left(\dfrac{-3a}{2}\right)^2+\left(\dfrac{b}{\boxed{2}}\right)^2}=\sqrt{\dfrac{\boxed{9}a^2}{\boxed{4}}+\dfrac{\boxed{b}^2}{\boxed{4}}}
5 0
3 years ago
Read 2 more answers
A+b=95<br> 4a+1.50b=267.5
Papessa [141]

9514 1404 393

Answer:

  • a=50
  • b=45

Step-by-step explanation:

We can subtract the second equation from 4 times the first:

  4(a +b) -(4a +1.5b) = 4(95) -(267.5)

  2.5b = 112.5 . . . . . simplify

  b = 45 . . . . . . . . . . divide by 2.5

  a = 95 -b = 50 . . . find 'a'

The solution is (a, b) = (50, 45).

5 0
2 years ago
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