The distance between points A (3, -5) and A' (2, -3) is 2.4 units.
Given that,
The points A (3, -5) and A' (2, -3).
We have to determine,
The distance between point A and A'.
According to the question,
The distance between two points is determined by using the distance formula.
Then,
The distance between points A (3, -5) and A' (2, -3) is,
Hence, The distance between points A (3, -5) and A' (2, -3) is 2.4 units.
For more details refer to the link given below.
brainly.com/question/8069952
Step-by-step explanation:
we know that
Work =f*d
=25*100
=2500Joule
therefore work done is 2500Joule
First, you need to change it from standard form to slope-intercept form. To do this, you have to add 3x to both sides. Now that y is by itself, divide by 5 on both sides. Your equation should now be y=3x+3. Then, graph the points. Your x-intercept should be at (-5,0) and your y- intercept should be at (0,3).
By applying concepts of <em>linear</em> functions, the graphs are related to the following expressions:
- (4/7) · x + 2
- x + 2
- (1/7) · x + 2
- - (1/7) · x + 2
- - x + 2
<h3>How to match a line with a given linear function</h3>
Graphically speaking, lines are described by <em>linear</em> functions, a kind of polynomials of grade 1, whose standard form is presented below:
y = m · x + b (1)
Where:
- x - Independent variable
- y - Dependent variable
- m - Slope
- b - Intercept
Please notice that the slope is represented graphically by the change in the y-variable divided by the change in the x-variable and the intercept is the location where the line passes through the y-axis. Hence, the <em>resulting</em> expressions are shown in this order:
- (4/7) · x + 2
- x + 2
- (1/7) · x + 2
- - (1/7) · x + 2
- - x + 2
To learn more on linear functions: brainly.com/question/9330192
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