How do you solve 2/3 [(5+3) ^-3]

1 answer:

7 0

$\dfrac{2}{3}[(5+3)^{-3}]=\dfrac{2}{3}(8)^{-3}\\\\\text{use}\ a^{-n}=\dfrac{1}{a^n}\\\\=\dfrac{2}{3}\cdot\dfrac{1}{8^3}=\dfrac{2}{3\cdot512}=\dfrac{1}{3\cdot256}=\dfrac{1}{768}$

You might be interested in

I need help putting the operations down and getting 17 and the next few questions

damaskus [11]

Answer:

i don't now

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

if i bottle flip a bottle 17 times and there is a ratio of 2 to 3 of it landing how many times will it land

blondinia [14]

The bottle will land about 11 out of the 17 times
hope i helped ( ಥـْـِـِـِـْಥ)

7 0

3 years ago

Help with this proof

mixer [17]

Essentially, what we need to do here is prove that BE=EC, BE=CB, and.or CE=BC therefore making it isosceles. With ∠AEC=∠DEB, we know AE=DE, so EC=EB (the points go in order). Therefore, as EC=EB, BEC is isosceles (it has at least 2 equal sides).

Feel free to ask further questions!

7 0

3 years ago

If $\sqrt{5+n}=7$, then what is the value of $n$?

alina1380 [7]

Answer:

Step-by-step explanation:

We can solve the equation by simplifying it.

$\sqrt{5+n}=7$ , let's square both sides.