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3 years ago

9

target sells tide detergent for $6.75 for 25 fluid ounces. walmart sells tide dergernt for $11.20 for 40 fl.oz. use the unit rat

e to determine which is a better buy

1 answer:

Aleks [24]3 years ago

4 0

Step-by-step explanation:

the cost per ounce at target would be .2688 and the cost per ounce ot walmart would be .28 so target would be the better buy.

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Find the volume and complete the table

suter [353]

Sorry I cant answer it as i dont understand the question im so sorry :(

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4 years ago

Which expression is equivalent to \frac{10q^5w^7}{2w^3}.\ \frac{4\left(q6\right)^2}{w^{-5}} for all values of q and w where the

mestny [16]

Answer:

$\frac{10q^5w^7}{2w^3}.\ \frac{4\left(q^6\right)^2}{w^{-5}} =20q^{17}w^9$

Step-by-step explanation:

Given

$\frac{10q^5w^7}{2w^3}.\ \frac{4\left(q^6\right)^2}{w^{-5}}$

Required

Determine the equivalent expression

$\frac{10q^5w^7}{2w^3}.\ \frac{4\left(q^6\right)^2}{w^{-5}}$

Simplify the first fraction

$\frac{5q^5w^7}{w^3}.\ \frac{4\left(q^6\right)^2}{w^{-5}}$

Apply law of indices on the first fraction;

$5q^5w^{7-3}.\ \frac{4\left(q^6\right)^2}{w^{-5}}$

$5q^5w^4.\ \frac{4\left(q^6\right)^2}{w^{-5}}$

$\ \frac{5q^5w^4*4\left(q^6\right)^2}{w^{-5}}$

Apply law of indices:

$5q^5w^4*4\left(q^6\right)^2 * w^{5}$

Evaluate the bracket

$5q^5w^4*4 * q^{12} * w^{5}$

Collect Like Terms

$5*4q^5* q^{12}*w^4 * w^{5}$

$20q^5* q^{12}*w^4 * w^{5}$

$20q^{5+12}*w^{4+5}$

$20q^{17}w^9$

Hence:

$\frac{10q^5w^7}{2w^3}.\ \frac{4\left(q^6\right)^2}{w^{-5}} =20q^{17}w^9$

7 0

3 years ago

Point e is located at -12 on the numbers line. Point f is located at 9 on the numbers line.

nikitadnepr [17]

The distance would be 21. to find the difference, add the absolute values so 12+9, which equals 21

6 0

4 years ago

Find the indicated limit, if it exists.

jok3333 [9.3K]

For the limit to exist, the limits from either side must also exist and be identical. We have

$\displaystyle\lim_{x\to2^-}f(x)=\lim_{x\to2}(x+3)=2+3=5$

$\displaystyle\lim_{x\to2^+}f(x)=\lim_{x\to2}(3-x)=3-2=1$

Since the limits do not match, the overall limit does not exist.

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3 years ago

Party trays, which cost $14.00 to make not including labor, are sold for $35.00. If two people work 8-hour shifts making the tra

umka21 [38]

Answer:

5.33 trays must be sold to cover all costs including labor...

Step-by-step explanation:

We have given:

Party trays, which cost $14.00 to make not including labor, are sold for $35.00.

Profit on party trays excluding labour cost = $35 - $14 = $21

Now we will find total labor cost for making party tray for a day

Total labor hours * wages per hour* No. of labors

= $7 * $8*2

= $112

Therefore to find how many trays must be sold to cover all costs including labor just divide total labour cost for making party tray for a day by profit on party trays excluding labour cost.

= $112/$21

= 5.33

It means 5.33 trays must be sold to cover all costs including labor...

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3 years ago

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