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3 years ago

The trainer's goal was to have Lucky gain weight. Was the goal met? Explain.

Mathematics

1 answer:

Aleks04 [339]3 years ago

7 0

Answer:

Yes the trainer was successful in an attempt for lucky to gain weight.

Step-by-step explanation:

Lucky was a weak and thin body shaped person who came to a gym trainer to gain weight. The trainer started to guide Lucky that he has to go for supplements and heavy weight lifting in order to gain weight. After 3 month's of hard work lucky has finally gained weight from 55 kg to 88 kgs.

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Best explained and correct answer gets brainliest.

cestrela7 [59]

It'd be B) because to make a triangle the sum of two sides has to be greater than the third side. 3+4=7, and 7>5, so...<span>voilà</span>

6 0

2 years ago

What is the height of a trapezoid with an area of 99 in.2 whose bases are 6 in. and 12 in.?

vladimir1956 [14]

Answer:

trapezoid area = ((sum of the bases) ÷ 2) • height

trapezoid area = ((6 + 12) / 2) * height

trapezoid area = 18 / 2 * height

height = 99/9 = 11

Step-by-step explanation:

7 0

2 years ago

(e+3)(e-5) expanded and simplified

Zarrin [17]

Step-by-step explanation:

$(e + 3)(e - 5) \\ e \times e + e \times ( - 5) + e \times e + e \times 3 \\ { e}^{2} + ( - 5e) + {e}^{2} + 3e \\ {2e}^{2} + ( - 2e)$

In this type of math equation, you have to multiply all members from the first part with the second part.

Expanded:

$e \times e+e \times (-5)+e \times e+e \times 3$

simplified:

${2e}^{2} + ( - 2e)$

8 0

2 years ago

(1+tanx)/(sinx+cosx)=secx

jek_recluse [69]

$\frac{1+\tan x}{\sin x+\cos x}=\sec x$ is proved

<h3><u>Solution:</u></h3>

Given that,

$\frac{1+\tan x}{\sin x+\cos x}=\sec x$ ------- (1)

First we will simplify the LHS and then compare it with RHS

$\text { L. H.S }=\frac{1+\tan x}{\sin x+\cos x}$ ------ (2)

$\text {We know that } \tan x=\frac{\sin x}{\cos x}$

Substitute this in eqn (2)

$=\frac{1+\frac{\sin x}{\cos x}}{\sin x+\cos x}$

On simplification we get,

$=\frac{\frac{\sin x+\cos x}{\cos x}}{\sin x+\cos x}$

$=\frac{\sin x+\cos x}{\cos x} \times \frac{1}{\sin x+\cos x}$

Cancelling the common terms (sinx + cosx)

$=\frac{1}{c o s x}$

We know secant is inverse of cosine

$=\sec x=R . H . S$

Thus L.H.S = R.H.S

$\frac{1+\tan x}{\sin x+\cos x}=\sec x$

Hence proved

5 0

3 years ago

What value of x is in the solution set of –5x – 15 > 10 + 20x?

Sunny_sXe [5.5K]

-5x - 15 > 10 + 20x...subtract 10 from both sides, add 5x to both sides
-10 - 15 > 20x + 5x ...simplify
-25 > 25x...divide both sides by 25
-25/25 > x ....reduce
-1 > x or x < -1 <===

6 0

3 years ago