Let the number of units of the first type be x and the number of units of the second type be y.
A. You expect to sell at least 100 printers this month. This means that:
A + B >= 100
For simplicity, we will work on the equal sign (A + B = 100) which is the minimum number of units to be sold.
This can be rewritten as: A = 100 - B .................> equation I
B. You expect to make a minimum profit of 4400. This means that:
50A + 40B >= 4400
Again for simplicity, we will work on the equal sign (50A + 40B = 4400) which is the minimum profit to be made
50A + 40B = 4400 ..................> equation II
Substitute with equation I in II:
50 (100-B) + 40B = 4400
5000 - 50B + 40B = 4400
5000 - 4400 = 50B - 40B
600 = 10B
B = 60
Substitute in equation I:
A = 100 - B = 100-60 = 40
Therefore, to minimize your cost and achieve your goals in number of selling units and profits:
you should buy at least 40 units from the first type and 60 units from the second type
The equation for this table of values is y = 6x + 1
Answer:
Option 1. F F → T is the answer.
Step-by-step explanation:
In this question the given conditional statements are
3×2 = 5 then 6 < 0
We have to find the truth value of these conditional statements.
Since multiplication of 3×2 = 6 therefore the truth value of this statement is False.
For the statement 6<0 truth value is false because 6 is always greater than 0.
Now we know in two statements P → Q, if they follow the Implication rule then truth value is False only when P is true and Q is false otherwise in every condition the truth value is True.
Therefore F F → T illustrates the statements of the question.
Answer:
5/2 = 2 1/2
Step-by-step explanation:
There are 2 parts in one half, meaning 2 halves equals 1.
If you have 5 halves, you of course would get an improper fraction.
To find the answer, dive the numerator by the denominator. 5 ÷ 2 gives you 2.5, or 2 1/2.
Think about it this way: How many times does will 2 go in to 5 evenly? Twice. 2 times 2 is 4, leaving you with one left over. Whatever the remainder is, is the numerator for the improper fraction, and the denominator stays the same.
Answer:
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Step-by-step explanation:
