Years for one serious accident is 10 year
<u>Given:</u>
Probability of having a serious accident = 10% every year
P(serious accident) = 0.1
Number of years = n
<u>Computation:</u>
Years for one serious accident = 1 / Probability of having a serious accident
Years for one serious accident = 1 / P(serious accident)
Years for one serious accident = 1 / 0.1
Years for one serious accident = 10 year
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Answer: 79.95 and 80.05
Step-by-step explanation: If the upper bound and lower bound is asked to a tenth then divide 0.1 by 2 and add 0.05 to 80.0 for the upper bound and minus 0.05 from 80.0 t get the lower bound.
Answer:
Vz = arccos(0.1673413807) = 80.37º
Step-by-step explanation:
The inverse function of the cosine is the arc cosine.
That means, that if we have that cos a = 1, a is the angle which has cosine equals 1, so a = arccos(1) = 0º.
In this problem, we have that:
cos(Vz) = 0.1673413807
Vz = arccos(0.1673413807) = 80.37º
Answer:
either 1/3 chance or 1/6 chance
Step-by-step explanation:
not exactly sure...
0.25 goes into 41 a total of 164 times. to get this answer you take 41 and divide it by 0.25 to get 164.