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Mamont248 [21]
3 years ago
15

The Jansen family drove a total of 240 miles on their road trip. This distance is 5 times the distance they drove on the first d

ay. How many miles did the family drive on the first day.
Mathematics
1 answer:
kompoz [17]3 years ago
8 0

Answer:

48 miles

Step-by-step explanation:

240/5 = 48

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USPshnik [31]

Answer:

x is +1

y is-5

Step-by-step explanation:

8 0
2 years ago
Indicate the answer choice that best completes the statement or answers
zysi [14]

Answer:

Option D. y = 5x + 1

Step-by-step explanation:

From the question given above, the following data were:

Input (x) >>>>>> Output (y)

0 >>>>>>>>>>>> 1

1 >>>>>>>>>>>> 6

2 >>>>>>>>>>>> 11

3 >>>>>>>>>>>> 16

4 >>>>>>>>>>>> 21

To know the the correct answer to the question, we shall apply the equation given in each option to see which will satisfy the table. This can be obtained as follow:

For Option a

y = 3x + 3

x = 0

y = 3(0) + 3

y = 0 + 3

y = 0

y = 3x + 3

x = 1

y = 3(1) + 3

y = 3 + 3

y = 6

For Option b

y = 5x – 4

x = 0

y = 5(0) – 4

y = 0 – 4

y = – 4

y = 5x – 4

x = 1

y = 5(1) – 4

y = 5 – 4

y = 1

For Option c

y = 10x – 9

x = 0

y = 10(0) – 9

y = 0 – 9

y = – 9

y = 10x – 9

x = 1

y = 10(1) – 9

y = 10 – 9

y = 1

For Option d

y = 5x + 1

x = 0

y = 5(0) + 1

y = 0 + 1

y = 1

y = 5x + 1

x = 1

y = 5(1) + 1

y = 5 + 1

y = 6

From the illustrations made above, only option d satisfy the table. Thus, option d gives the correct answer to the question.

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3 years ago
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2 years ago
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Ilia_Sergeevich [38]
A=41% B=3% hope this helps
4 0
2 years ago
Write an equation of the line that passes through (18, 2) and is parallel to the line 3y−x=−12
miskamm [114]

keeping in mind that parallel lines have the same exact slope, hmmmm what's the slope of the line above anyway?

\bf 3y-x=-12\implies 3y=x-12\implies y=\cfrac{x-12}{3}\implies y = \cfrac{x}{3}-\cfrac{12}{3} \\\\\\ y = \stackrel{\stackrel{m}{\downarrow }}{\cfrac{1}{3}}x-4\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}

so we're really looking for the equation of a line whose slope is 1/3 and runs through (18,2)

\bf (\stackrel{x_1}{18}~,~\stackrel{y_1}{2})~\hspace{10em} \stackrel{slope}{m}\implies \cfrac{1}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{2}=\stackrel{m}{\cfrac{1}{3}}(x-\stackrel{x_1}{18}) \\\\\\ y-2=\cfrac{1}{3}x-6\implies y=\cfrac{1}{3}x-4

3 0
3 years ago
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