Using the ratios,
suppose:
width=8x
length=15x
let d be the diagonal
thus; using Pythagorean theorem:
d^2=(8x)^2+(15x)^2
=64x^2+225x^2
=289x^2
d=17x
or x=d/17
width=8x=8d/17
length=15x=15d/17
Answer:
(mxt) miles
Step-by-step explanation:
hope that this is helpful.
Answer:
3
Step-by-step explanation:
you'd have w^2, w, and your constant
1) 8v+w+7-8v+2w
=w+7+2w
=3w+7
-----------------------------
2) 4c^2+6c-3c^2-2c-3
=c^2+6c-2c-3
=c^2+4c-3
-------------------------------
3) z^3+5z+3z^2+1-4-2z^2
=z^3+z^2+5z+1-4
=z^3+z^2+5z-3