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2 years ago

Find the length and show work. (100pts)

Mathematics

2 answers:

lbvjy [14]2 years ago

6 0

Answer:

Acute Angle

Step-by-step explanation:

It is an acute angle because

If the angle is less than 90 degrees it is acute.

k0ka [10]2 years ago

3 0

Answer:

its an acute angle

Step-by-step explanation:the only angle that small is an acute angle

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40.91 percent

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If x > 0 and y < 0, where is the point (x, y) located?

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Quadrant 4

Step-by-step explanation:

x > 0 means towards right of the origin

y < 0 means below the origin

So Quadrant 4

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2 years ago

Segment LM is the mid segment of Trapezoid ABCD.AB=×+8,LM=4×+3,andDC=215.what is the value of x

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3 years ago

In rectangle $ABCD$, $AD=1$, $P$ is on $\overline{AB}$, and $\overline{DB}$ and $\overline{DP}$ trisect $\angle ADC$. Write the

Studentka2010 [4]

<h3>Answer:</h3>

w+x+y+z = 12

<h3>Explanation:</h3>

When right angle ADC is divided into three equal parts (trisected), each of those parts is 90°/3 = 30°. Thus, ∠CDB = ∠PBD = ∠PDB = 30°.

The sides of a 30°-60°-90° triangle are in the proportion 1 : √3 : 2. Hence BD = 2, and PD = PB = 2/√3 = (2/3)√3.

Then the perimeter of ∆BDP is ...

... perimeter ∆BDP = BD + DP + PB

... = 2 + (2/3)√3 + (2/3)√3

... = 2 + (4√3)/3 . . . . . . . . w=2, x=4, y=3, z=3

w + x + y + z = 2+4+3+3 = 12

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2 years ago

In t hours the train has traveled s miles. Find the formula for v, the speed of the train (in mph) in terms of t and s. Find the

Digiron [165]

Answer:

Part 1 .

As per the given statement: In t hours the train has traveled s miles.

Distance of the train = s mile

Time = t hours

Formula for :

Speed of the train(v) = $\frac{\text{Distance of the train}}{\text{Time}}$

$v = \frac{s}{t}$ mph .....[1]

Substitute the value of t = 3 hours and s = 180 miles in [1], to solve for v;

$v = \frac{180}{3} = 60 mph$

Therefore, the speed of the train(v) is, 60 mph

Part 2.

Similarly,

The formula for speed of the train (v) is given by;

$v =\frac{s}{t}$

Substitute the value of t = 2.5 hours and s = 225 miles to solve for v;

$v = \frac{225}{2.5} = 90 mph$

Therefore, the speed of the train(v) is, 90 mph

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2 years ago

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