Use the distance formula: D=sqrt((x2-x1)^2+(y2-y1)^2)
Plug in:
D=sqrt((9-8)^2+(-1-2)^2)
D=sqrt(1^2+(-3)^2)
D=sqrt(1+9)
D=sqrt(10)
So the distance is about 3.16 units
Hope this helped!
Answer:
Part 1
The mistake is Step 2: P + 2·x = 2·y
Part 2
The correct answer is
Step 2 correction: P - 2·x = 2·y
(P - 2·x)/2 = y
Step-by-step explanation:
Part 1
The student's steps are;
Step 1; P = 2·x + 2·y
Step 2: P + 2·x = 2·y
Step 3: P + 2·x/2 = y
The mistake in the work is in Step 2
The mistake is moving 2·x to the left hand side of the equation by adding 2·x to <em>P </em>to get; P + 2·x = 2·y
Part 2
To correct method to move 2·x to the left hand side of the equation, leaving only 2·y on the right hand side is to subtract 2·x from both sides of the equation as follows;
Step 2 correction: P - 2·x = 2·x + 2·y - 2·x = 2·x - 2·x + 2·y = 2·y
∴ P - 2·x = 2·y
(P - 2·x)/2 = y
y = (P - 2·x)/2
This question is based on cognitive assessment method .
Given line of letters is-
B E F B E B I E F S E E D P F E S J E E J D E D E P J E T
In the following line of letters, the letter that follows the seventh E-- B E F B E B I E F S E E D P F E S J E E J D E D E P J E T
The answer is letter E.
Answer:
v8
Step-by-step explanation:
what the other guy said!
In three dimensions, the cross product of two vectors is defined as shown below
Then, solving the determinant
In our case,
Where we used the formula for AxB to calculate ixj.
Finally,
Thus, (i+j)x(ixj)=i-j
