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3 years ago

First right answer will get brainlist

Mathematics

2 answers:

Nuetrik [128]3 years ago

7 0

$y: \frac{1}{5}=20 \\ y=20* \frac{1}{5}= \frac{20}{5}=4$

garri49 [273]3 years ago

3 0

Answer is 4 .............

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Let Y be a random variable with a density function given by

Neporo4naja [7]

From the given density function we find the distribution function,

$F_Y(y)=P(Y\le y)=\displaystyle\int_{-\infty}^y f_Y(t)\,\mathrm dt=\begin{cases}0&\text{for }y$

(a)

$F_{U_1}(u_1)=P(U_1\le u_1)=P(3Y\le u_1)=P\left(Y\le\dfrac{u_1}3\right)=F_Y\left(\dfrac{u_1}3\right)$

$\implies F_{U_1}(u_1)=\begin{cases}0&\text{for }u_1$

$\implies f_{U_1}(u_1)=\begin{cases}\frac{{u_1}^2}{18}&\text{for }-3\le u_1\le3\\0&\text{otherwise}\end{cases}$

(b)

$F_{U_2}(u_2)=P(3-Y\le u_2)=P(Y\ge3-u_2)=1-P(Y$

$\implies F_{U_2}(u_2)=\begin{cases}0&\text{for }u_2$

$\implies f_{U_2}(u_2)=\begin{cases}\frac32(u_2-3)^2&\text{for }2\le u_2\le4\\0&\text{otherwise}\end{cases}$

(c)

$F_{U_3}(u_3)=P(Y^2\le u_3)=P(-\sqrt{u_3}\le Y\le\sqrt{u_3})=F_Y(\sqrt{u_3})-F_y(\sqrt{u_3})$

$\implies F_{U_3}(u_3)=\begin{cases}0&\text{for }u_3$

$\implies f_{U_3}(u_3}=\begin{cases}\frac32\sqrt u&\text{for }0\le u\le1\\0&\text{otherwise}\end{cases}$

5 0

3 years ago

At a pizza shop 80% of customers order pizza

Marta_Voda [28]

Answer:

Your question is no completed

6 0

3 years ago

If DM=45, what is the value of r?

amm1812

Answer:

Step-by-step explanation:

6 0

3 years ago

30 pts + BRAINLIEST

ivanzaharov [21]

Answer:

Number of permutations = 5040

Step-by-step explanation:

We are given the word 'INNOVATIVE', that has total 10 letters.

Now, we are asked to form words using exactly 4 letters at a time i.e. out of 10 letters we are using 4.

Therefore, the number of permutations that can be formed using 4 letters are = P(10,4)

i.e. $10_{P_{4} }$

= $\frac{10!}{(10-4)!}$

= $\frac{10!}{6!}$

= $\frac{10*9*8*7*6!}{6!}$

= 10*9*8*7

= 5040

8 0

3 years ago

Read 2 more answers

If an item that originally cost $13 is increased to $19, what is the percentage of increase in the item?

Evgesh-ka [11]

Original cost (OC) = $13

New cost (NC) = $19

Percentage increase = $\frac{NC - OC}{OC} *100 = \frac{19 - 13}{13} * 100 = \frac{6}{13} * 100$

= 46.15 %

4 0

3 years ago