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KatRina [158]
3 years ago
12

Given certain information, what is the value of x4-y4?

Mathematics
1 answer:
Pepsi [2]3 years ago
3 0

Well right off the bat, I can see a good reason why it should boggle.

If (x+y)=6 and (x-y)=2, then (x+y)(x-y) would be 12. It can't be 20.

The first 4 lines on the paper are inconsistent, so the question in the 5th line can't be calculated.

Another possible source of uncertainty (for us, anyway) is the remarkable similarity between the way you write ' Y ' and the way you write ' 4 ' . For example, look at the ' Y⁴ ' (I think ...) in the last line.

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¿Cómo influye el fenómeno de capilaridad en la vida de las plantas?
Arlecino [84]

Answer:

Plants use capillary action to bring water up the roots and stems to the rest of the plant. Therefore, if the plant could not do this the plant would die.

Step-by-step explanation:

3 0
3 years ago
Which is greater than, less than, and equal to 18 tons or 36,000 lbs?
slamgirl [31]
36000 lbs = 16329.325 kg
18 ton = 18000kg

18 ton is greater
5 0
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1. What is 8 percent of 20?
leonid [27]

The answer to your question is 1.6

7 0
3 years ago
The circle at the right represents a planet. The radius of the planet is about 6300 km. Find the distance d to the horizon that
faust18 [17]

Answer:

224.54 km

Step-by-step explanation:

A right triangle is formed, where h + r = 4 + 6300 = 6304 km is the hypotenuse, r = 6300 km is one leg and d is the other leg. By Pythagorean theorem:

6304² = 6300² + d²

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3 0
3 years ago
Write the partial fraction decomposition fro the ration expression below
zlopas [31]
\dfrac{5x-2}{(x-1)^2}=\dfrac a{x-1}+\dfrac b{(x-1)^2}
5x-2=a(x-1)+b

Since 5x-2=5x-5+3=5(x-1)+3, it follows that a=5 and b=3, so

\dfrac{5x-2}{(x-1)^2}=\dfrac5{x-1}+\dfrac3{(x-1)^2}

\dfrac{x^3+x^2+x+2}{x^4+x^2}=\dfrac{x^3+x+x+2}{x^2(x^2+1)}=\dfrac ax+\dfrac b{x^2}+\dfrac{cx+d}{x^2+1}
x^3+x^2+x+2=ax(x^2+1)+b(x^2+1)+(cx+d)x^2
x^3+x^2+x+2=(a+c)x^3+(b+d)x^2+ax+b

When x=0, you find that b=2. It's also clear that a=1. So the remaining constants must be 1+c=1\implies c=0 and 2+d=1\implies d=-1, and so you get

\dfrac{x^3+x^2+x+2}{x^4+x^2}=\dfrac1x+\dfrac2{x^2}-\dfrac1{x^2+1}
6 0
3 years ago
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