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2 years ago

If y=6 when x=2 over 3 find x when y=12

Mathematics

1 answer:

AlexFokin [52]2 years ago

6 0

Answer:

4/3 or 1 1/3

Step-by-step explanation:

So if y = 6, when x = 2/3. Then, x would equal 1 and 1/3, because 12 is twice the amount of 6, so you'd also multiply 2/3 by 2.

(To multiply a whole number by a fraction, first multiply the whole number by the numerator and then divide that by the denominator. For example: 2 × 2 = 4, since you can't really divide 4 by 3 it would stay as is, but you can turn it to a mixed number. 4/3 is the same as 1 whole and an extra 1/3, or in other words 1 1/3).

Hope this helped :)

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A simple random sample of 20 third-grade children from a certain school district is selected, and each is given a test to measur

ICE Princess25 [194]

Answer:

Option C) 5.62 points

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 20

Sample mean score = 64

Sample standard deviation, s = 12

Degree of freedom =

$=n-1\\=20-1\\=19$

We have to calculate margin of error for a 95% confidence interval.

Formula for margin of error:

$t_{critical}\times \displaystyle\frac{s}{\sqrt{n}}$

Putting the values, we get,

$t_{critical}\text{ at degree of freedom 19 and}~\alpha_{0.05} = \pm 2.093$

$2.093\times (\displaystyle\frac{12}{\sqrt{20}} )\\\\ =5.6161\approx 5.62$

Thus, the correct answer is

Option C) 5.62 points

4 0

3 years ago

Change the subject of the formula L = v 4kt - p to k.

Romashka [77]

Answer:

$\boxed{k = \frac{L^2 + p}{4t}}$

General Formulas and Concepts:

Algebra I

Basic Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Step-by-step explanation:

Step 1: Define

Identify given.

$\displaystyle L = \sqrt{4kt - p}$

Step 2: Solve for k
We can use equality properties to help us rewrite the equation to get k as our subject:

Let's first square both sides:

$\displaystyle\begin{aligned}L = \sqrt{4kt - p} & \rightarrow L^2 = \big( \sqrt{4kt - p} \big) ^2 \\& \rightarrow L^2 = 4kt - p \\\end{aligned}$

Next, add p to both sides:

$\displaystyle\begin{aligned}L = \sqrt{4kt - p} & \rightarrow L^2 = \big( \sqrt{4kt - p} \big) ^2 \\& \rightarrow L^2 = 4kt - p \\& \rightarrow L^2 + p = 4kt \\\end{aligned}$

Next, divide 4t by both sides:

$\displaystyle\begin{aligned}L = \sqrt{4kt - p} & \rightarrow L^2 = \big( \sqrt{4kt - p} \big) ^2 \\& \rightarrow L^2 = 4kt - p \\& \rightarrow L^2 + p = 4kt \\& \rightarrow \frac{L^2 + p}{4t} = k \\\end{aligned}$