If parallelogram JKLM is rotated 270° counterclockwise around the origin, what are the coordinates of the endpoints of the side
congruent to side KL in the image parallelogram? A. K’(-4, -6); L’(3, -3) B. K’(6, 4); L’(3, 3) C. K’(-6, -4); L’(-3, -3) D. K’(-4, 6); L’(-3, -3)
2 answers:
The <em>correct answer</em> is:
B) K’(6, 4); L’(3, 3)
Explanation:
A 270° clockwise rotation maps every point (x, y) to (y, -x). (It negates the x-coordinate and then switches it and the y-coordinate.)
This means the endpoints of the side congruent to KL, K' and L', would be mapped as:
K'(-4, 6)→(6, 4)
L'(-3, 3)→(3, 3)
Answer:
the user above is correct
Step-by-step explanation:
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