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cupoosta [38]
3 years ago
14

Creat a table of values for the equation y=-x-3

Mathematics
1 answer:
nadya68 [22]3 years ago
4 0

Answer:

x /\ y

1  /\ -4

2 /\ -5

3 /\ -6

4 /\ -7

... /\ ...

Step-by-step explanation:

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PLEASE HELP FOR BRAINLIEST <br><br> if UW bisects
Semenov [28]

Answer:

If it does bisect it would be Tuv

Step-by-step explanation:

It would join it together

8 0
3 years ago
Read 2 more answers
8 plus 3 cubed over 12-7
Finger [1]

Answer:

7

Step-by-step explanation:

8+3³/12-7

8+27/5

35/5

7

4 0
3 years ago
Find a number x such that g(x) = -4
mel-nik [20]

Answer:

C: x = 7

Step-by-step explanation:

The easiest way to do this is to simply try all of the x-vales given as options.

Option 1: x = -1

Since -1 \leq 0, we'll use the first equation.

g(x)=\mid x \mid - 2\\g(-1)=\mid -1 \mid - 2 = 1 - 2 = -1

As we can see, g(-1) is not -4.

Option 2: x = 3

Since 0 < 3 < 4, we'll use the 2nd equation.

g(x) = x-3\\g(3) = 3-3 = 0

Not -4.

Option 3: x = 7

Since 4 \leq 7, we'll use the 3rd equation.

g(x) = 3-x\\g(7) = 3-7 = -4

Tada! We have found a number such that g(x) = -4, it is 7. Since we only need to find a number, not all numbers, we don't have to check the last option. However, if you're curious:

Option 4: x = 4

Since 4 \leq 4 (less than <em>or equal to</em>), we'll use the 3rd equation.

g(x) = 3-x\\g(4) = 3-4 = -1

3 0
3 years ago
A researcher wishes to see if the average number of sick days a worker takes per year is less than 5. A random sample of 30 work
Lana71 [14]

Answer:

No. At a significance level of 0.01, there is not enough evidence to support the claim that the average number of sick days a worker takes per year is significantly less than 5.

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that the average number of sick days a worker takes per year is significantly less than 5.

Then, the null and alternative hypothesis are:

H_0: \mu=5\\\\H_a:\mu< 5

The significance level is 0.01.

The sample has a size n=30.

The sample mean is M=4.8.

The standard deviation of the population is known and has a value of σ=1.2.

We can calculate the standard error as:

\sigma_M=\dfrac{\sigma}{\sqrt{n}}=\dfrac{1.2}{\sqrt{30}}=0.219

Then, we can calculate the z-statistic as:

z=\dfrac{M-\mu}{\sigma_M}=\dfrac{4.8-5}{0.219}=\dfrac{-0.2}{0.219}=-0.913

This test is a left-tailed test, so the P-value for this test is calculated as:

\text{P-value}=P(z

As the P-value (0.181) is bigger than the significance level (0.01), the effect is not significant.

The null hypothesis failed to be rejected.

At a significance level of 0.01, there is not enough evidence to support the claim that the average number of sick days a worker takes per year is significantly less than 5.

3 0
3 years ago
Carmen is considering joining one of the two movie clubs. Movie Galore charges a monthly membership fee of $10, plus $0.50 per m
lakkis [162]
25 movies.

So basically you start and end at 1 month so,

Galore Cost = 
$10
Galore Per Movie = 
0.5 x 25 = 12.5 + 10 = $22,5

Cinephile Cost = 
$15
Cinephile Per Movie = 
0.25 x 25 = 6.25 + 15 = 21.25

These questions are just trial and error
5 0
4 years ago
Read 2 more answers
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