Question

PLEASE HELP

Answer 1

Answer:

The area of the resulting cross section is $78.5\ m^{2}$

Step-by-step explanation:

we know that

The resulting cross section is a circle congruent with the circle of the base of cylinder

therefore

The area is equal to

$A=\pi r^{2}$

we have

$\pi=3.14$

$r=10/2=5\ m$ -----> the radius is half the diameter

substitute the values

$A=(3.14)(5)^{2}=78.5\ m^{2}$