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Basile [38]
3 years ago
15

The length of a rectangle is 4 units more than its width. The area of the rectangle is 25 more than 4 times the width.

Mathematics
2 answers:
lisabon 2012 [21]3 years ago
8 0

Answer:

its d. 5

Step-by-step explanation:

never [62]3 years ago
6 0

Answer:

B or D ( answer = 5 => Two options is one! One of the options should be 5)

Note: The width of a rectangle will never be negative.

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Help me please Solve for r <br> d=rt
Vika [28.1K]

Watch closely.    I'll try to go slow.
Stop me if I go too fast, or if I do anything that you don't understand.

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You said                               d      =  r t

Divide each side by ' t ' :    d / t  =  r

5 0
3 years ago
Mathematics textbook grade 4
n200080 [17]

Answer:

so what are u trying to say ,,!!!

Step-by-step explanation:

HAVE A NICE DAY

3 0
3 years ago
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Stacy paid $54 for 6 pizzas, which is a rate of $ ? per pizza.
irakobra [83]

Answer: it’s 9

Step-by-step explanation:

54 divined by 6 = 9

7 0
3 years ago
Will upvote brainiest answer and add friend
Mashcka [7]

Answer:

68°

Step-by-step explanation:

ABD is a right angle and the measure of it is 90°

m<CBD + m<ABC = m<ABD

4x + 52° + 8x - 10 = 90° add like terms

12x + 42° = 90°

12x = 48°

x = 4

m<CBD is 4x + 52° replace x with 4

4×4 + 52 = 68°

8 0
4 years ago
Andrew claims the initial value and y - intercept are the same thing on a graph. Is he correct?
Agata [3.3K]

Answer:

We conclude that the initial value and y-intercept are the same thing on a graph.

Please check the attached graph of the equation y = 2x+1.

Step-by-step explanation:

We know that the initial value on a graph is basically the out-put value y of the point where the line meets or crosses the y-axis.

In other words, the initial value is the y-value or output of the point at x = 0

For example,

Let the equation

y = 2x+1

substitute x = 0

y = 2(0)+1

y = 0+1

y = 1

Thus, the initial value of the equation y = 2x+1 is: y = 1

Please check the attached graph of the equation y = 2x+1.

It is clear from the graph that at x = 0, the value of y = 1.

Thus, at y = 1, the line meets the y-axis.

Hence, the initial value of the line is: y = 1

Similarly, we know that the value of the y-intercept can be determined by setting x = 0 and determining the corresponding value of y.

For example,

Let the equation

y = 2x+1

substitute x = 0

y = 2(0)+1

y = 0+1

y = 1

Thus, the y-intercept of y = 2x+1 is y = 1.

Please check the attached graph of the equation y = 2x+1.

It is clear from the graph that at x = 0, the value of y = 1.

Therefore, the y-intercept of y = 2x+1 is y = 1.

Conclusion:

Therefore, we conclude that the initial value and y-intercept are the same thing on a graph.

Please check the attached graph of the equation y = 2x+1.

6 0
3 years ago
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