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3 years ago

The length of a rectangle is 4 units more than its width. The area of the rectangle is 25 more than 4 times the width.

Mathematics

2 answers:

lisabon 2012 [21]3 years ago

8 0

Answer:

its d. 5

Step-by-step explanation:

never [62]3 years ago

6 0

Answer:

B or D ( answer = 5 => Two options is one! One of the options should be 5)

Note: The width of a rectangle will never be negative.

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Answer:

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Mattie uses the discriminant to determine the number of zeros the quadratic equation 0 = 3x2 – 7x + 4 has. Which best describes

Eduardwww [97]

For $ax^2+bx+c=0$ the discriminant is $b^2-4ac$

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3 years ago

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BaLLatris [955]

Answer:

Step-by-step explanation:

1 In general, given a{x}^{2}+bx+cax

+bx+c, the factored form is:

a(x-\frac{-b+\sqrt{{b}^{2}-4ac}}{2a})(x-\frac{-b-\sqrt{{b}^{2}-4ac}}{2a

−b+√

−4ac

)(x−

−b−√

−4ac

)

2 In this case, a=1a=1, b=-2b=−2 and c=-2c=−2.

(x-\frac{2+\sqrt{{(-2)}^{2}-4\times -2}}{2})(x-\frac{2-\sqrt{{(-2)}^{2}-4\times -2}}{2})(x−

2+√

(−2)

−4×−2

)(x−

2−√

(−2)

−4×−2

)

3 Simplify.

(x-\frac{2+2\sqrt{3}}{2})(x-\frac{2-2\sqrt{3}}{2})(x−

2+2√

)(x−

2−2√

)

4 Factor out the common term 22.

(x-\frac{2(1+\sqrt{3})}{2})(x-\frac{2-2\sqrt{3}}{2})(x−

2(1+√

)

)(x−

2−2√

)

5 Cancel 22.

(x-(1+\sqrt{3}))(x-\frac{2-2\sqrt{3}}{2})(x−(1+√

))(x−

2−2√

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6 Simplify brackets.

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)(x−

2−2√

)

7 Factor out the common term 22.

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)(x−

2(1−√

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8 Cancel 22.

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)(x−(1−√

))

9 Simplify brackets.

(x-1-\sqrt{3})(x-1+\sqrt{3})(x−1−√

)(x−1+√

)

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Ann [662]

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