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marusya05 [52]
3 years ago
7

Match the y-coordinates with their corresponding pairs of x-coordinates on the unit circle. the x coordinates to choose from are

: - 2 times the square root of 10/11 - 4 times the square root of 6/11 - 1/ the square root of 11 - 6 times the square root of 2/11
Mathematics
1 answer:
vaieri [72.5K]3 years ago
6 0
Of the four x-coordinates to choose only 1/√(11) belongs can belong to the unit circle.

The other three x-coordinates are greater than 1, then they are out of the unit circle.

The unit circle formula is x^2 +y^2 = 1

Then to find the y-coordinate given the x-coordinate you can solve for y from that formula:

y^2 = 1 - x^2

y = (+/-)√(1-x^2)

Substitute the value of x

y = (+/-)√{1 - [1/√(11)]^2} = (+/-) √{(1 - 1/11} =(+/-) √ {(11 -1)/11 =(+/-)√(10/11) ≈ +/- 0.95


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<h2> </h2><h2>x = 5 -  \frac{4}{3} y - 2z</h2>

Step-by-step explanation:

<h3><u>Question</u><u>:</u><u>-</u></h3>
  • To solve for x

<h3><u>Equation</u><u>:</u><u>-</u></h3>
  • 3x + 4y + 6z = 15

<h3><u>Solution</u><u>:</u><u>-</u></h3>

=> 3x + 4y + 6z = 15

  • <em>[</em><em>On</em><em> </em><em>subtracting</em><em> </em><em>both</em><em> </em><em>sides</em><em> </em><em>with</em><em> </em><em>4y</em><em>]</em>

=> 3x + 4y + 6z - 4y = 15 - 4y

  • <em>[</em><em>On</em><em> </em><em>Simplification</em><em>]</em>

=> 3x + 6z = 15 - 4y

  • <em>[</em><em>On</em><em> </em><em>subtracting</em><em> </em><em>both</em><em> </em><em>sides</em><em> </em><em>with</em><em> </em><em>6z</em><em>]</em>

=> 3x + 6z - 6z = 15 - 4y - 6z

  • <em>[</em><em>On</em><em> </em><em>Simplification</em><em>]</em>

=> 3x = 15 - 4y - 6z

  • <em>[</em><em>On</em><em> </em><em>dividing</em><em> </em><em>both</em><em> </em><em>sides</em><em> </em><em>with</em><em> </em><em>3</em><em>]</em>

=  >  \frac{3x}{3}  =  \frac{15 - 4y - 6z}{3}

  • <em>[</em><em>On</em><em> </em><em>Simplification</em><em>]</em>

=  > x = 5 -  \frac{4}{3} y - 2z \: (ans)

3 0
2 years ago
Read 2 more answers
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