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marusya05 [52]
3 years ago
7

Match the y-coordinates with their corresponding pairs of x-coordinates on the unit circle. the x coordinates to choose from are

: - 2 times the square root of 10/11 - 4 times the square root of 6/11 - 1/ the square root of 11 - 6 times the square root of 2/11
Mathematics
1 answer:
vaieri [72.5K]3 years ago
6 0
Of the four x-coordinates to choose only 1/√(11) belongs can belong to the unit circle.

The other three x-coordinates are greater than 1, then they are out of the unit circle.

The unit circle formula is x^2 +y^2 = 1

Then to find the y-coordinate given the x-coordinate you can solve for y from that formula:

y^2 = 1 - x^2

y = (+/-)√(1-x^2)

Substitute the value of x

y = (+/-)√{1 - [1/√(11)]^2} = (+/-) √{(1 - 1/11} =(+/-) √ {(11 -1)/11 =(+/-)√(10/11) ≈ +/- 0.95


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Find the value of x
Bess [88]

Step-by-step explanation:

the answer is

2x+4x =90

6x=90

x=15°

3 0
3 years ago
The 9th and the 12th term of an arithmetic progression are 50 and 65 respectively. find the common difference
Rzqust [24]

The first term of the arithmetic progression exists at 10 and the common difference is 2.

<h3>How to estimate the common difference of an arithmetic progression?</h3>

let the nth term be named x, and the value of the term y, then there exists a function y = ax + b this formula exists also utilized for straight lines.

We just require a and b. we already got two data points. we can just plug the known x/y pairs into the formula

The 9th and the 12th term of an arithmetic progression exist at 50 and 65 respectively.

9th term = 50

a + 8d = 50 ...............(1)

12th term = 65

a + 11d = 65 ...............(2)

subtract them, (2) - (1), we get

3d = 15

d = 5

If a + 8d = 50 then substitute the value of d = 5, we get

a + 8 * 5 = 50

a + 40 = 50

a = 50 - 40

a = 10.

Therefore, the first term is 10 and the common difference is 2.

To learn more about common differences refer to:

brainly.com/question/1486233

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4 0
2 years ago
How are the volume formulas of prisms and cylinders similar? How are they<br> different?
AysviL [449]

Answer:

They are both similar in the way that the formula is base multiplied by height. They are different because of the type of shape on the base.

Step-by-step explanation:

hope this helps

7 0
3 years ago
Help!!!!!!!!!!!!!!!!!!!!!!
zhuklara [117]

Answer:

see below

Step-by-step explanation:

9 ^-5 * 9^-3

When multiplying these we ADD the exponents:

9^-5 * 9^-3

= 9^(-5 + -3)

= 9 ^-8

= 1/9^8  Option A


2.    2^14 / 2^7   This is a division so we SUBTRACT the exponents:-

= 2^(14 - 7)  

= 2^7   (answer)

3.    If the triangle is a right angled one then it will obey Pythagoras Theorem so:-

13^ = x^2 + 5&2

x^2 = 13^2 - 5^2

x^2 = 144

x = 12    (answer)


4.   The last choice is a crucial step.

The total area of the triangles is the same in both large squares so  the area of the large  square e^2 = a^2 + b^2 ( the 2 squares in the left side large square).

5 0
3 years ago
So yall... what's up?
Alexeev081 [22]
I believe it is option choice A, because that is the most reasonable and efficient
3 0
4 years ago
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