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3 years ago

6

2 + 2 +2+6+5+6+6+7655566656655555565868675364363623737384949498484848448383838838337, 784484848484847488448585858585858585858585

8+456464646566756655655664354542422324356788980

2 answers:

Jlenok [28]3 years ago

7 0

Is this even a real question to answer that you need urgent help on because you can literally use a calculator

agasfer [191]3 years ago

3 0

bro what kinda mf question is this

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Find the values of x,y,z. This diagram is not a scale.

Serjik [45]

Important:
   The sum of the three angles inside
      every triangle is always 180°.

First, look at the left triangle alone.
Two of its angles are 46° and 58° . (46° + 58° ) = 104°
That leaves (180° - 104° ) = 76° degrees for the third angle.
The third angle in that triangle is 'x'.
   x = 76° .

At the point where 'x' and 'z' come together:
'x' and 'z' are a "linear pair".
Placed side-by-side, they form a straight line.
So (x + z) = 180° .
But x = 76°.
So z = (180° - 76°).    z = 104° .

Now look at the the skinny triangle on the right alone.
The angle at the top is 13°, and z = 104°.
(13° + 104°) = 117° .
That leaves (180° - 117°) = 63° for the third angle.
'y' is the third angle.
   y = 63° .

3 0

3 years ago

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18. If a university wants to maintain a 14:1 ratio between students and teachers, how many teachers would be needed to accommoda

LekaFEV [45]

64 is the answer because if its 14 to 1 divide 896 by 14 and you would get 64 teachers

8 0

4 years ago

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4x-2y=7<br> -3x+3y=10<br> Find the point of intersection of the equations

garri49 [273]

4x-2y=7 (1)
-3x+3y=10 (2)
3y= 3x+10
y= x+10/3 (3)
sub (3) into (1)
4x-2(x+10/3)=7
4x-2x-20/3=7
2x-20/3=7
+20/3 +20/3
2x= 41/3
x= (41/3) / 2
x= 41/6
sub x= 41/6 into (3)
y= 41/6+10/3
= 61/6

Therefore the point of intersection is (41/6, 61/6)

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3 years ago

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The length is three times the height. The height is one inch less than the width. The volume is 108 cubic inches. Find the dimen

alexandr402 [8]

Answer:

3×9×4

Step-by-step explanation:

The volume for a box is b×h×w

With a bit of trial and error, you will quickly find out that the height and width, are small numbers.

When you try 3 for the height you will see that it works.

3×3=9 this is the length

the width is one inch more than the height so for

3×9×4=108

7 0

3 years ago

Pirate Jack has an equal number of gold and silver coins. If Pirate Jack splits all of his coins into 7 equal piles for his parr

Tcecarenko [31]

Answer:

The least possible number of coins the Pirate has = 81

Step-by-step explanation:

Given:

Pirate Jack has equal number of gold and silver coins.

When the pirate splits the coins into 7 equal piles he has 4 coins left.

When the pirate splits the coins into 11 equal piles he has 4 coins left.

Every pile has at least 1 coin.

To find the least possible number of coins Pirate Jack has.

Solution:

In order to find the least possible number of coins pirate Jack has, we must find the least common multiple of the number of piles the coins are split into.

So, the least common multiple of 7 and 11 can be found by listing the multiples.

$7= 7,14,21,28...............,77$

$11=11,22,33,44,55,66,77$

So, we find the least common multiple of 7 and 11 is 77.

Number of coins left = 4

Total number of coins the pirate must have = $77+4 =81$

We can check the answer by dividing 81 by 7 and 11. I both cases we get remainder = 4.

So, the least possible number of coins the pirate has = 81

6 0

4 years ago