Solve the equation -10=-6+2c
2 answers:
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Answer:
see explanation
Step-by-step explanation:
(1)
Given
3(x + 3)² - 1 = - 13 ( add 1 to both sides )
3(x + 3)² = - 12 ( divide both sides by 3 )
(x + 3)² = - 4 ( take the square root of both sides )
x + 3 = ± = ± 2i ( subtract 3 from both sides )
x = - 3 ± 2i ← complex conjugate roots
(2)
Given
3x² - 12x + 27 = 0 ( subtract 27 from both sides )
3x² - 12x = - 27 ( divide through by 3 )
x² - 4x = - 9
To complete the square
add ( half the coefficient of the x- term )² to both sides
x² + 2(- 2)x + 4 = - 9 + 4
(x - 2)² = - 5 ( take the square root of both sides )
x - 2 = ± = ± i
( add 2 to both sides )
x = 2 ± i ← complex conjugate roots