Answer: LAST OPTION.
Step-by-step explanation:
The Pythagorean Theorem states the following relationship between the three sides of a triangle that has an angle of 90 degrees, known as "Right triangle":

Where "a"is the hypotenuse and "b" and "c" are the legs of the right triangle.
If the triangle ABC is a right triangle then AB must be equal to
, then, you need to substitute the values into
to check this:

Then the triangle ABC is not a right triangle.
Therefore, the statement that justifies why this triangle is not a right triangle is:

5m-8=3m+8
(Plus the '8' to both sides)
5m=3m+16
(Subtract '3m' from both sides)
2m=16
(Divide by 2)
m=8
Its is true that C ⊆ D means Every element of C is present in D
According to he question,
Let C = {n ∈ Z | n = 6r – 5 for some integer r}
D = {m ∈ Z | m = 3s + 1 for some integer s}
We have to prove : C ⊆ D
Proof : Let n ∈ C
Then there exists an integer r such that:
n = 6r - 5
Since -5 = -6 + 1
=> n = 6r - 6 + 1
Using distributive property,
=> n = 3(2r - 2) +1
Since , 2 and r are the integers , their product 2r is also an integer and the difference 2r - 2 is also an integer then
Let s = 2r - 2
Then, m = 3r + 1 with r some integer and thus m ∈ D
Since , every element of C is also an element of D
Hence , C ⊆ D proved !
Similarly, you have to prove D ⊆ C
To know more about integers here
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(7 + 5) x 6 + 3. (7 + 5 = 12, 12 x 6 = 72, 72 + 3 = 75.)
Answer: 0.907571211 also known as 52 degrees
Step-by-step explanation: I hope this helps :)