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2 years ago

Show all your work plz help now

Mathematics

1 answer:

Studentka2010 [4]2 years ago

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1) $3.2
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Find the distance between the points (-4,5), (-12,5)

posledela

Answer:

d = 8

Step-by-step explanation:

For:

(X1, Y1) = (-4, 5)

(X2, Y2) = (-12, 5)

Distance Equation Solution:

d=(−12−(−4))2+(5−5)2−−−−−−−−−−−−−−−−−−−−√

d=(−8)2+(0)2−−−−−−−−−−√

d=64+0−−−−−√

d=6–√4

d=8

Therefore, the distance between (-4,5), (-12,5) is 8.

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2 years ago

What is the logarithmic form of 11² = 121?

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Logbase11(121)=2. The base of the log to the power of y (outside number) = the number in the parenthesis (x).

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Complete the function table for y=2.5x−8 .

Black_prince [1.1K]

Answer:

x=3.2

Step-by-step explanation:

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Please answer this question now

Alexeev081 [22]

Answer:

$Area = 400.4 m^2$

Step-by-step Explanation:

Given:

∆UVW,

m < U = 33°

m < V = 113°

VW = u = 29 m

Required:

Area of ∆UVW

Solution:

Find side length UV using Law of Sines

$\frac{u}{sin(U)} = \frac{w}{sin(W)}$

U = 33°

u = VW = 29 m

W = 180 - (33+113) = 34°

w = UV = ?

$\frac{29}{sin(33)} = \frac{w}{sin(34)}$

Cross multiply

$29*sin(34) = w*sin(33)$

Divide both sides by sin(33) to make w the subject of formula

$\frac{29*sin(34)}{sin(33)} = \frac{w*sin(33)}{sin(33)}$

$\frac{29*sin(34)}{sin(33)} = w$

$29.77 = w$

$UV = w = 30 m$ (rounded to nearest whole number)

Find the area of ∆UVW using the formula,

$area = \frac{1}{2}*u*w*sin(V)$

$= \frac{1}{2}*29*30*sin(113)$

$= \frac{29*30*sin(113)}{2}$

$Area = 400.4 m^2$ (to nearest tenth).

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2 years ago

What is the answer to the math problem

ale4655 [162]

Is this the right answer

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3 years ago

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