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1 year ago

How do you categorize each of these questions as one of these types

Mathematics

1 answer:

Sindrei [870]1 year ago

6 0

The statistical questions are:

On average, how many books does each person in the United States read each year
Which book was read most by students in the class, this summer

The non-statistical questions are:

How many acts are there in the play Romeo and Juliet
How many books are in the class right not

<h3>How to categorize the questions?</h3>

As a general rule, questions whose answers can be determined using a single data point are non-statistical questions.

Using the above rule, we have the non-statistical questions to be:

How many acts are there in the play Romeo and Juliet
How many books are in the class right not

As a general rule, questions whose answers cannot be determined using a single data point are statistical questions.

Using the above rule, we have the statistical questions to be:

On average, how many books does each person in the United States read each year
Which book was read most by students in the class, this summer

Also, both statistical questions are numerical

Read more about statistical questions at

brainly.com/question/12150562

#SPJ1

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Select the functions that have a value of -1. sin180° cos180° tan180° csc180° sec180° cot180°

kupik [55]

We have to break each degree in terms of 90

A) $sin180^\circ=sin(90\times2+0)$

Which is in third quadrant, therefore sine is negative hence

$sin(90\times2+0)= -sin0 ^\circ = 0$

B) $cos180^\circ =cos(90\times2+0)$

Which is in third quadrant, therefore cosine is negative hence

$cos(90\times2+0)= -cos0^\circ = -1$

C) $tan180^\circ=tan(90\times2+0)$

Which is in third quadrant, therefore tangent is positive hence

$tan(90\times2+0)= tan0^\circ = 0$

D) $csc180^\circ=csc(90\times2+0)$

Which is in third quadrant, therefore cosec is negative hence

$cosec(90\times2+0)= -csc0^\circ =$ not defined

E) $sec180^\circ=sec(90\times2+0)$

Which is in third quadrant, therefore secant is negative hence

$sec(90\times2+0)= -sec0^\circ = -1$

F) $cot180^\circ=cot(90\times2+0)$

Which is in third quadrant, therefore tangent is positive hence

$cot(90\times2+0)= cot0^\circ =$ not defined

Hence only $cos 180^\circ$ and

$sec180^\circ$ have value -1

Hope this will help

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Answer:

c= (f-d)/ab

Step-by-step explanation:

abc+d = f
Subtract f from both sides so abc= f-d
Divide by ab from both sides so c = (f-d)/ab

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