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4 years ago

5

Write a number in each box to make an equation that has no real solution. Explain why this equation has no solution. 4(a-2) + a

= __a - __

1 answer:

borishaifa [10]4 years ago

5 0

Answer:

4(a-2)+a=4a-2 No solution

Step-by-step explanation:

This would never be true. Try plugging in <em>a</em> as 1.

4(1-2)+1 isn't equal to 4(1)-2.

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Add the following fractions. See the image below

LenKa [72]

Answer:

$\dfrac{19}{840}$

Step-by-step explanation:

The given fraction is:

$\dfrac{1}{168}+\dfrac{3}{180}$

We need to solve it.

The LCM of 168 and 180 is 2520.

So,

$\dfrac{1}{168}+\dfrac{3}{180}=\dfrac{15+3\cdot14}{2520}\\\\=\dfrac{19}{840}$

So, the required answer is equal to $\dfrac{19}{840}$ .

3 0

3 years ago

You can get the max points i can give for this :)

andriy [413]

Answer:

${a}^{2} + {b}^{2} = {c}^{2} \\ {a}^{2} + {9}^{2} = {17}^{2} \\ {a}^{2} = 289 - 81 \\ {a}^{2} = 208 \\ a = 14.42cm$

3 0

3 years ago

What is the slope of the line that passes through the points (-10, 9)(−10,9) and (-12, 7) ?(−12,7)? Write your answer in simples

Mashutka [201]

Answer:

I Had A Problem In This Too Lol Here Was Correct For Me

Step-by-step explanation:

Identify the coordinates (x₁,y₁)and(x₂,y₂). We will use the formula to calculate the slope of the line passing through the points (3,8) and (-2, 10).

Input the values into the formula. This gives us (10 - 8)/(-2 - 3).

Subtract the values in parentheses to get 2/(-5).

Simplify the fraction to get the slope of -2/5.

7 0

3 years ago

Read 2 more answers

Describe how to write 0.0000672 in scientific notation

prohojiy [21]

You have to remeber that you have to have a number that is less than 10, but equal or greater than 1! Okay since your trying to get between 1-10 with this number you would move the decimal point 5 places to the right. And since you are going back it is going to be negative so the answer would be 6.72*10^-5

4 0

4 years ago

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17. Identify the amplitude, period, and vertical shift for the

Stella [2.4K]

Answer:

$f(x)=2cos(x+\frac{\pi}{2})+3$

Step-by-step explanation:

Because the function is symmetric about the y-axis, using the cosine function is most appropriate.

<u>Refer to the equation for a cosine function:</u>

<u /> $f(x)=acos(bx+c)+d$ <u />

Amplitude: $|a|$

Period: $\frac{2\pi}{|b|}$

Phase shift: $-\frac{c}{b}$

Midline: $y=d$

The amplitude would be the average of the maximum and minimum y-values of the function, which would be $|a|=|\frac{5-1}{2}| =|\frac{4}{2}| =|2|=2$ .

The value of $b$ in $\frac{2\pi}{|b|}$ represents the length of the period, so since the length of the period is $2\pi$ , this means that $b=\frac{2\pi}{|2\pi|} =1$ .

The phase shift, $-\frac{c}{b}$ , describes the horizontal shift of a function. Because the phase shift is $-\frac{\pi}{2}$ , then we can set up the equation $-\frac{\pi}{2}=-\frac{c}{1}$ where we determine $c=\frac{\pi}{2}$ .

The midline (or vertical shift), $d$ , is the horizontal line that passes through between the maximum and minimum points, which the function oscillates. In this case, the midline would be located at the line $y=3$ , therefore, $d=3$ .

Putting all our information together, your final equation is:

$f(x)=2cos(x+\frac{\pi}{2})+3$

3 0

3 years ago