Answer is
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Given:
n = 20, sample size
xbar = 17.5, sample mean
s = 3.8, sample standard deiation
99% confidence interval
The degrees of freedom is
df = n-1 = 19
We do not know the population standard deviation, so we should determine t* that corresponds to df = 19.
From a one-tailed distribution, 99% CI means using a p-value of 0.005.
Obtain
t* = 2.8609.
The 99% confidence interval is
xbar +/- t*(s/√n)
t*(s/√n) = 2.8609*(3.8/√20) = 2.4309
The 99% confidence interval is
(17.5 - 2.4309, 17.5 + 2.4309) = (15.069, 19.931)
Answer: The 99% confidence interval is (15.07, 19.93)
Answer:
2.5 or 5/2
Step-by-step explanation:
2x-3=2
2x=5 (both sides plus 3)
x=5/2 or 2.5(divid by 2 on both sides)
Answer:
32n
Step-by-step explanation:
4(8n) = 4 * 8 * n = 32 * n = 32n
thank, 5 star, and brainliest if helpful!
