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3 years ago

What is the measurement of angle ABC

Mathematics

1 answer:

Sonbull [250]3 years ago

3 0

The answer to your question is 124°

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A circle has a circumference of 16π. What is the radius of the circle?

oksian1 [2.3K]

Radius = Circumference / 2π
r = 16π/2π
r = 8

In short, Your Answer would be 8

Hope this helps!

7 0

3 years ago

Read 2 more answers

ABC is translated 4 unite to the loft and 8 unito up, thon roflooted

gayaneshka [121]

Answer:

(-3, 13)

Step-by-step explanation:

Coordinate of A is (7,5)

4 units to the left means (7-4, 5) --> (3,5)

8 units up means (3, 5+8) --> (3,13)

Reflected across the y-axis means that the sign of whatever x coordinate you have now will be reversed.

So (-3,13)

3 0

3 years ago

PLEASE HELP ME ASAP I WILL MARK YOU AS BRILLIANT please help with these three

GalinKa [24]

Answer:

26: x=34

28: x=17

30: m=30

Step-by-step explanation:

26: 2x+22=90

subtract 22

2x=68

divide by 2

x=34

28: 18+3x+21=90

add 18 and 21

3x+39=90

subtract 39

3x=51

divide by 3

x=17

30: 43+87+m+20=180

add 43 and 87 and 20

m+150=180

subtract 150

m=30

6 0

3 years ago

On a coordinate plane, triangle A B C is shown. Point A is at (0, 0), point B is at (3, 4), and point C is at (3, 2). What is th

Elena L [17]

Answer:

The area of triangle for the given coordinates is 1.5 $\sqrt{4.6}$

Step-by-step explanation:

Given coordinates of triangles as

A = (0,0)

B = (3,4)

C = (3,2)

So, The measure of length AB = a = $\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

Or, a = $\sqrt{(3-0)^{2}+(4-0)^{2}}$

Or, a = $\sqrt{9+16}$

Or, a = $\sqrt{25}$

∴ a = 5 unit

Similarly

The measure of length BC = b = $\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

Or, b = $\sqrt{(3-3)^{2}+(2-4)^{2}}$

Or, a = $\sqrt{0+4}$

Or, b = $\sqrt{4}$

∴ b = 2 unit

And

So, The measure of length CA = c = $\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

Or, c = $\sqrt{(3-0)^{2}+(2-0)^{2}}$

Or, c = $\sqrt{9+4}$

Or, c = $\sqrt{13}$

∴ c = $\sqrt{13}$ unit

Now, area of Triangle written as , from Heron's formula

A = $\sqrt{s\times (s-a)\times (s-b)\times (s-c)}$

and s = $\frac{a+b+c}{2}$

I.e s = $\frac{5+2+\sqrt{13}}{2}$

Or. s = $\frac{7+\sqrt{13}}{2}$

So, A = $\sqrt{(\frac{(7+\sqrt{13})}{2})\times ((\frac{(7+\sqrt{13})}{2})-5)\times (\frac{7+\sqrt{13}}{2}-2)\times (\frac{7+\sqrt{13}}{2}-\sqrt{13})}$

Or, A = $\sqrt{(\frac{(7+\sqrt{13})}{2})\times (\frac{(\sqrt{13}-3)}{2})\times (\frac{4+\sqrt{13}}{2})\times (\frac{7-\sqrt{13}}{2})}$

Or, A = $\frac{3}{2}$ × $\sqrt{1+\sqrt{13} }$

∴ Area of triangle = 1.5 $\sqrt{4.6}$

Hence The area of triangle for the given coordinates is 1.5 $\sqrt{4.6}$ Answer

7 0

3 years ago

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Four friends at a party popped 3/4 of a bag of popcorn. They ate half of what was popped. What fraction of the popcorn in the ba

steposvetlana [31]

Your answer is... they ate 2/4 or 1/2 of the bag of popcorn.

3 0

3 years ago