Answer:
Step-by-step explanation:
Find the limit of x to 0 of 4•Sec(4x)^-2
We know that, Sec4x = 1 / Sin4x
Then,
Lim x → 0: 4•(1 / Sin4x)^-2
Lim x → 0: 4•(Sin4x)²
Then,
Lim x → 0: 4(Sin(4×0))²
Lim x → 0: 4(Sin0)²
Lim x → 0: 4
Then, the limit as x → 0 is 4.
The correct answer is 4
Option A
Answer:
Step-by-step explanation:
F(x) = x² - 2x + 1
= (x - 1)²
By comparing this equation with the vertex form of the quadratic equation,
y = (x - h)² + k
Here, (h, k) is the vertex
Vertex of the parabola → (1, 0)
x-intercepts → (x - 1)² = 0
x = 1
y-intercepts → y = (0 - 1)²
y = 1
Now we can draw the graph of the given function,
From this graph,
As x → 0,


f(0) = (0 - 1)²
= 1
Since, 
Therefore, given function is continuous at x = 0.
C is what I think/Know for sure
Answer:
A line....
Step-by-step explanation:
Plz be more clear with your question!
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