1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
artcher [175]
3 years ago
8

1. Factor 3x2y2 − 2xy2 − 8y2. Show your work.

Mathematics
1 answer:
andrew-mc [135]3 years ago
8 0
3 x^{2}  y^{2} -2x y^{2} -8 y^{2}  \\ = 3 x^{2}  y^{2} -6x y^{2}+4x y^{2} -8 y^{2}  \\ =(3 x^{2}  y^{2} -6x y^{2})+(4x y^{2} -8 y^{2}) \\ =3xy^{2} (x-2)+4 y^{2}(x-2) \\ =(3xy^{2}+4 y^{2})(x-2) \\ = y^{2} (3x+4)(x-2)
You might be interested in
Does anyone know what 2/6 plus 1/8 is?
Kay [80]

Answer:

3/14

Step-by-step explanation:

hope this helps

7 0
3 years ago
The scores on a math test are normally distributed with a mean of 78 and a standard deviation of 6. The test scores range from 0
Hunter-Best [27]

Answer:

The estimate for the number of students who took the test is 23.

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean = 78

Standard deviation = 6

Since the normal distribution is symmetric, 50% of the students had scores above the mean and 50% had scores below the mean.

Proportion of students who scored between 72 and 90:

72 = 78 - 6

So 72 is one standard deviation below the mean.

Of the 50% of the students who scored below the mean, 68% scored above 72.

90 = 78 + 2*6

So 90 is two standard deviations above the mean.

Of the 50% of the students who scored above the mean, 95% scored below 72.

Then

0.68*0.5 + 0.95*0.5 = 0.815

81.5% of the students scored between 72 and 90.

Nineteen students had test scores between 72 and 90. Estimate the number of students who took the test.

19 is 91.5% = 0.815 of the total number of students.

How much is 100% = 1?

19 - 0.815

x - 1

0.815x = 19

x = \frac{19}{0.815}

x = 23.3

Rounding to the nearest whole number

The estimate for the number of students who took the test is 23.

6 0
4 years ago
Megan answered 18 questions correctly on a test.That is 75% of the total number of questions.How many questions were on the test
meriva
We can use this equation to find how many questions there were on the test:

.75x = 18

This equation means 75% of what is 18.

.75x = 18
Divide both sides by .75
x = 24

There were 24 questions on the test.
7 0
3 years ago
Read 2 more answers
Molly was curious if quadrilateral A, B, C, D and E, F, G, H were congruent, so she tried to map one figure onto the other using
Readme [11.4K]

Answer: Choice C. No error. Molly is correct

Note how BC is 4 units high while FG is 5 units high. We don't have a match. So there is no way the figures are the same regardless of rigid transformations.

3 0
4 years ago
What ratio would you use to convert 880 yards to miles. Remember that there are 1,760 yards in one mile.
timofeeve [1]
Divide 880/1760 to get 0.5 miles
5 0
4 years ago
Other questions:
  • Please help me, i'm not the best at math. Thank you !
    6·1 answer
  • Mimi sells super-sized cookies for $1.50 each and estimates she has expenses of $10 to make one batch of cookies. If the inequal
    8·1 answer
  • Find the value of a
    9·2 answers
  • Simplify: 3.59 x 106 : 9.5 x 10-6
    5·2 answers
  • Solve the problem <br> ( SHOW your work )<br><br><br> 10x – 3 = 8x + 5
    14·1 answer
  • I will give u brainliest
    8·2 answers
  • 3/2x-8=hx+2 <br> This equation will have zero solutions when h=<br> Because you get zero
    15·1 answer
  • What is the diameter of a circle given the equation x^2+5x=−8y−y^2
    8·1 answer
  • 2.) x/2 = 1 Solving equations.
    5·2 answers
  • A piecewise function g(x) is represented by the graph.
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!