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denpristay [2]
3 years ago
5

If you had 6 5/7 and you have 3/4 away how much do u hav

Mathematics
2 answers:
Cerrena [4.2K]3 years ago
7 0

Answer:

You have 5 27/28

Step-by-step explanation:

  1. 6 20/28 - 21/28= 5 27/28
  2. 5 27/28
Papessa [141]3 years ago
3 0

Answer:

6 1/12.

Step-by-step explanation:

6 5/6 - 3/4

=  6 + (5/6 - 3/4)

The LCD of 6 and 4 is 12 so we have:

6 + (10/12 - 9/12)

= 6 1/12

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krek1111 [17]

Answer:

9=0.6q where q is the number of questions on the exam.

Step-by-step explanation:

3 0
3 years ago
Help! I'll give brainy
Ne4ueva [31]
The answer is A. 5/12
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Any REAL help on #16 above??? Can someone check my answer?
babymother [125]

Answer:

The answer to your question is:th first option is correct.

Step-by-step explanation:

Here we have and hyperbola with center (0, 1), and the hyperbola is horizontal because x² is positive.

Equation

y - k = ±\frac{b}{a} (x - h)

Process

Find a, b

                a² = 9    

               a = 3

                b² = 5

              b = √5

              h = 0    and k = 1

Substitution

              y - 1 = ±\frac{√5}{3} (x - 0)

Equation 1

            y = \frac{\sqrt{5} }{3} x + 1

Equation 2

           y = - \frac{\sqrt{5} }{3} x + 1  

3 0
3 years ago
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A company determined that the marginal​ cost, C' (x )of producing the xth unit of a product is given by C' (x )= x^3- 6x. Find t
Rashid [163]

Answer:

C(x) = \frac{x^4}{4}-3x^2+3,000

Step-by-step explanation:

The marginal cost function, C'(x), is the derivate of the cost function, C(x).

Therefore, we can obtain the cost function by finding the integral of the marginal cost function:

C(x) = \int\ {C'(x)} \, dx \\C(x) = \int\ {(x^3-6x)} \, dx \\C(x) = \frac{1}{4} x^4-3x^2+a

Where 'a' is a constant and represents fixed costs. If fixed costs are $3,000, the cost function is:

C(x) = \frac{x^4}{4}-3x^2+3,000

3 0
3 years ago
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