Answer:
N(1)=50 is a minimum
N(15)=4391.7 is a maximum
Step-by-step explanation:
<u>Extrema values of functions
</u>
If the first and second derivative of a function f exists, then f'(a)=0 will produce values for a called critical points. If a is a critical point and f''(a) is negative, then x=a is a local maximum, if f''(a) is positive, then x=a is a local minimum.
We are given a function (corrected)


(a)
First, we take its derivative

Solve N'(t)=0

Simplifying

Solving for t

Only t=1 belongs to the valid interval 
Taking the second derivative

Which is always positive, so t=1 is a minimum
(b)

N(1)=50 is a minimum
(c) Since no local maximum can be found, we test for the endpoints. t=1 was already determined as a minimum, we take t=15
(d)

N(15)=4391.7 is a maximum
Answer:
50 students per bus and 9 students per van
Step-by-step explanation:
I just guessed until I got it right, so I don't really have a method. If I ever find a better way of doing it, I'll edit my answer.
Answer:
B.
- 4x - 5
Step-by-step explanation:
(p о n) (x) is the same thing as (p(n(x))
We know n(x) = x - 5, so let's input that into our expression
(p(x - 5))
Since we know p(x) = x^2 + 6x, let's replace the x with the new value x-5. Now our expression is:
p(x) = (x - 5)^2 + 6(x - 5)
Now all we have to do is simplify.
(x - 5)^2 is the same as: (x - 5)(x - 5)
Using the foil method, it simplifies to: x^2 - 10x + 25
6 (x - 5) = 6x - 30
Now our expression is: x^2 - 10x + 25 + 6x - 30
Combine like terms: x^2 - 4x - 5
The expression is:
- 4x - 5
Answer:
X=11
m<wxz= 23
Step-by-step explanation:
hope this helps branliest please
Since Christian sets aside $60 per month for daily coffee, and McDonalds sells coffee for $ 1, and The Bean Sprout sells a cup of coffee for $3, to create an equation that represents the combinations of coffee options that allow Christian to stay in his budget and provide 2 combinations that use his entire budget, 1 combination that would be under budget, and 1 combination that would be over his budget, the following linear equation must be proposed:
M + BS = 60
2 combinations using the entire budget =
- 15 McDonalds + 15 The Bean Sprout = 15 + 45 = 60
- 30 McDonalds + 10 The Bean Sprout = 30 + 30 = 60
1 combination under budget =
- 15 McDonalds + 10 The Bean Sprout = 15 + 30 = 45
1 combination over budget =
- 30 McDonalds + 30 The Bean Sprout = 30 + 90 = 120
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