Question

It took my question down twice here's a real math question I guess

Answer 1

Answer:

$n-3$

Interval notation: $(-\infty, -10)\cup(-3,\infty)$

Step-by-step explanation:

First inequality:

$n+8$

Therefore, this inequality restricts:

$n \in \mathrm{R};\: n$

Second inequality:

$< 8+n-3$

Therefore, this inequality restricts:

$n \in \mathrm{R};\: n>-3$

Therefore, with both of these restrictions together, we have:

$\fbox{ n \in \mathrm{R}; n-3 }\\\mathrm{or\:}\fbox{ n-3 }\\\mathrm{or\:}\fbox{ (-\infty, -10)\cup(-3,\infty) }$.