What is the general form of the equation for the given circle?

Mathematics

1 answer:

Westkost [7]3 years ago

7 0

I think the answer is B or C

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Find a solution to the equation 4(x + 7) = 38

yKpoI14uk [10]

Answer:

4(x+7)=38

4x+28=38

4x=38-28

4x=10

(divide by 4)

x=2whole number 2/4

=2whole number 1/2

or x=2.5

6 0

3 years ago

Find the value of Z. A)7 B)9 C)11 D)12

Gala2k [10]

As per the isosceles triangle theorem, if the two base angles are congruent then the legs are also congruent, so we must set the two legs equal to each other:

2z - 15 = 9

Add 15 to both sides:

15 - 15 = 0
15 + 9 = 24

Divide 2 from each side:

2z = 24

2z/2 = z

24/2 = 12

z = 12

Hence, the answer would be D: z = 12

4 0

3 years ago

Read 2 more answers

Jada ran 15.25 kilometers. Han ran 8,500 meters. Who ran farther?

Thepotemich [5.8K]

Answer:

Jada

Step-by-step explanation:

We are given Jada's distance in kilometers and Han's distance in meters. To compare the two we need to have them both in the same unit of measurement.

One kilometer is equal to 1000 meters, so Jada ran 15.25*1000=15250 meters.

Compared to Han, who ran 8500 meters, Jada ran farther. 15250>8500.

4 0

3 years ago

Please help, I’ll mark your answer as brainliest!

statuscvo [17]

Answer:

$(x-230)^2+(y-220)^2=6100$

Step-by-step explanation:

The equation for a circle is $(x-h)^2+(y-k)^2=r^2$ , where $(h,k)$ is the vertex of the circle and $r$ is the radius. Immediately, since the center of the circle is given, we know what $h$ and $k$ are. $h$ is 230 and $k$ is 220.

The only thing we need to find is the radius, which will just be the distance from the center (230,220) to a point on the circumference (170,170). The distance between them can be calculated using the distance formula, which is really just the Pythagorean Theorem rearranged. The formula states that $d=\sqrt{x^2+y^2}$ , where $x$ is the change in the x-coordinates of the two points and $y$ is the change in the y-coordinates of the two points. Plug-in $x$ for 60 and $y$ for 50 to get $d=\sqrt{50^2+60^2}$ . Solve for $d$ , arriving at $\sqrt{6100}$ . Therefore, the radius of the circle is $\sqrt{6100}$ .