All categories

4 years ago

This is what i need help with

Mathematics

1 answer:

ch4aika [34]4 years ago

5 0

Answer:

B) 60

Step-by-step explanation:

They both equal each other,

5x+15=7x-3

And solve!

15+3=7x-5x

18=2x

X=9

Plug X into the angels.

5(9)+15

45+15

You might be interested in

X^2+14x-15=0 solve by completing square<br>

Softa [21]

Answer:

${x}^{2} + 14x - 15 = 0 \\ {x}^{2} - x + 15x -15 = 0 \\ x(x - 1) + 15(x - 1) = 0 \\ (x - 1)(x + 15) = 0 \\ \boxed{x = 1} \\ \boxed{x = - 15}$

<h3><u>x=1 and x=</u><u>-</u><u>15</u> is the right answer.</h3>

7 0

3 years ago

I need this equation done I don’t have a calculator. I am doing Car Purchasing for 30-3 math

riadik2000 [5.3K]

Answer:

864.0555 should be your answer.

3 0

3 years ago

7. By using binomial expansion show that the value of (1.01)^12 exceed the value of (1.02)^6 by 0.0007 correct to four decimal p

BlackZzzverrR [31]

Binomial expansion is used to factor expressions that can be expressed as the power of the sum of two numbers.

The proof that (1.01)^12 exceeds (1.02)^6 by 0.0007 is $\mathbf{(1.01)^{12} - (1.02)^6 \approx 0.0007 }$

The expressions are given as:

$\mathbf{(1.01)^{12}\ and\ (1.02)^6}$

A binomial expression is represented as:

$\mathbf{(a + b)^n = \sum\limits^n_{k=0}^nC_k a^{n - k}b^k}$

Express 1.01 as 1 + 0.01

So, we have:

$\mathbf{(1.01)^{12} = (1 + 0.01)^{12}}$

Apply the above formula

$\mathbf{(1.01)^{12} = ^{12}C_0 \times 1^{12 - 0} \times 0.01^0 + ......... .......... + ^{12}C_{12} \times 1^{12 - 12} \times 0.01^{12} }}$

$\mathbf{(1.01)^{12} = 1 \times 1 \times 1 + ......... .......... + 1 \times 1 \times 10^{-24} }}$

$\mathbf{(1.01)^{12} = 1 + ......... .......... + 10^{-24} }}$

This gives

$\mathbf{(1.01)^{12} = 1.1268\ (approximated)}$

Similarly,

Express 1.02 as 1 + 0.02

So, we have:

$\mathbf{(1.02)^6 = (1 + 0.02)^6}$

Apply $\mathbf{(a + b)^n = \sum\limits^n_{k=0}^nC_k a^{n - k}b^k}$

$\mathbf{(1.02)^6 = ^6C_0 \times 1^{6 - 0} \times 0.02^0 + ^6C_1 \times 1^{6 - 1} \times 0.02^1 +.............. + ^6C_6 \times 1^{6 - 6} \times 0.02^6 }$ $\mathbf{(1.02)^6 = 1 \times 1 \times 1 + 6 \times 1 \times 0.02 +.............. + 1 \times 1 \times 6.4 \times 10^{-11} }$

$\mathbf{(1.02)^6 = 1 + 0.12 +.............. + 6.4 \times 10^{-11} }$

This gives

$\mathbf{(1.02)^6 = 1.1261\ (approximated) }$

Calculate the difference as follows:

$\mathbf{(1.01)^{12} - (1.02)^6 \approx 1.1268 - 1.1261 }$

$\mathbf{(1.01)^{12} - (1.02)^6 \approx 0.0007 }$

The above equation means that:

(1.01)^12 exceed the value of (1.02)^6 by 0.0007

Read more about binomial expansions at:

brainly.com/question/9554282

7 0

3 years ago

Clark has a box of nickels and dimes that totals $1.90. there are a total of 27 coins. how many nickels and dimes does he have?

Andrej [43]

$0.05(n) + $0.10(d) = $1.90
n + d = 27
n + d - d =27 - d
n = 27 - d

$0.05(27-d) + $0.10(d) = $1.90
1.35 - 0.05d + 0.10d = $1.90
1.35 +0.05d = $1.90
1.35 - 1.35 +0.05d = $1.90 -1.35
0.05d = 0.55
0.05d/0.05 = 0.55/0.05
d = 11

n = 27 - 11
n = 16

$0.05(16) + $0.10(11) = $1.90
$0.80 + $1.10 = $1.90
$1.90 = $1.90

4 0

3 years ago

Tìm các chữ số a, b , c biết a/-5=b/-7=c/2 và a-b+c=-28

choli [55]

Answer:

a=35,b=49,c=-14

Step-by-step explanation:

$\frac{a}{-5} =\frac{b}{-7} =\frac{c}{2} =r(say)\\a=-5r,b=-7r,c=2r\\a-b+c=-5r+7r+2r=4r=-28\\r=\frac{-28}{4}=-7\\a=-5 \times -7=35\\b=-7 \times -7=49\\c=2 \times -7=-14$

8 0

3 years ago