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zepelin [54]
3 years ago
11

Please hurry

Mathematics
1 answer:
Olenka [21]3 years ago
4 0

Answer:

B.8K-168/K-12

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A rope factory produces ropes that have been measured to be able to lift 500 pounds, with a standard deviation of 6 pounds. One
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It's C. it does not ship because 480 is more than 2.57 deviations from 500



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A slice is made perpendicular to the base of a right rectangular prism as shown. What is the area of the resulting two-dimension
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Step-by-step explanation:

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A car travels 2 1/3 miles in 3 1/2 minutes at a constant speed. Write an equation to represent the car travels in miles and minu
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Answer:

d = 0.666t , where d is in miles and t is in minutes.

d = 39.94h, where d is in miles and h is in hours.

Step-by-step explanation:

A car travels 2\frac{1}{3} = 2.33 miles in 3\frac{1}{2} = 3.5 minutes at a constant speed.

Let the relation between the distance (d) traveled by car in miles after traveling t minutes is d = kt ......... (1)

Now, putting d = 2.33 miles and t = 3.5 minutes in the above equation we get,

2.33 = 3.5k

⇒ k = 0.666 (Approx.)

So, the equation (1) becomes d = 0.666t. (Answer)

Let us assume that the relation between the distance (D) traveled by car in miles after traveling h hours is d = Kh ............ (2)

Now, putting D = 2.33 miles and T = 3.5/60 = 0.058 hours in the above equation, we get

2.33 = 0.058K

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So, the equation (2) we get, d = 39.94h (Answer)

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3 years ago
Whats the distance between {-4 , 12} and {18 , 12}
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3 years ago
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Aria paid $75,000 for her house. Its property value increased by 2.2% per year. When Aria sold her house after eleven years, how
astra-53 [7]

Answer:

When Aria sold her house after eleven years it worth was <u>$95,300</u>.

Step-by-step explanation:

Given:

Aria paid $75,000 for her house. Its property value increased by 2.2% per year.

Now, to find the worth of Aria house when sold after eleven years.

Let the amount of house after eleven years be x.

Amount Aria paid for her house (A) = $75,000.

Rate of property increased per year (r) = 2.2%.

Time (t) = 11 years.

Now, to get the amount of house after eleven years we put formula:

x=A\times (1+\frac{r}{100})^{11}

x=75000\times (1+\frac{2.2}{100})^{11}

x=75000\times (1+0.022)^{11}

x=75000\times (1.022)^{11}

x=75000\times 1.2704

x=95280.

<em>The amount of house after eleven years to the nearest hundred dollars is $95,300.</em>

Therefore, when Aria sold her house after eleven years it worth was $95,300.

3 0
3 years ago
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