Answer:
<em>x = 0.05</em>
<em>x = 1.57</em>
Step-by-step explanation:
The given equation is:

Moving all terms to the left side:

Now we define a function:

The solutions of the equation are the values of x such that y=0.
Since the function cannot be solved by algebraic methods, we use a graphing tool.
Those points where the graph crosses the x-axis are solutions of the equation.
Please refer to the graph in the figure below.
We can clearly identify there are two solutions at
x = 0.05
x = 1.57
Answer:1.0%
Step-by-step explanation:
hopes it help
Answer:
c^2 +17c -5
Step-by-step explanation:
I like to line them up vertically
2c^2 +7c - 1
- (c^2 -10c+4)
----------------------
Distribute the minus sign
2c^2 +7c - 1
- c^2 +10c-4
----------------------
c^2 +17c -5
Answer:
C
Step-by-step explanation:
✔️First, solve for r:
r/2 ≤ 3
Multiply both sides by 2
r/2 × 2 ≤ 3 × 2
r ≤ 6
This implies that possible value of r is equal to 6 or less than 6.
Graphing this on a number line, the line with a shaded circle, indicating that 6 is included, starts at 6 and points to the left.
This indicates that value of r ranges from 6 and below.
The graph is C.