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3 years ago

How do I find an intersection? >·<

Mathematics

1 answer:

snow_tiger [21]3 years ago

3 0

I was actually just learning this. ^-^

To find the intersection, look at the numbers. and see what numbers do both groups have in common.

In this case, we have { 2, 4, 6, 9 } and { 3, 5, 8 }

As you can see, they both have nothing in common. Number wise.

So the answer would be Null.

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3 more than the product of 3 and y

Fudgin [204]

Answer:

3y+3

Step-by-step explanation:

pls give brainly

4 0

3 years ago

Help!! 50 points and brainliest!

Viktor [21]

Answer:

Second choice:

$x=2t$

$y=4t^2+4t-3$

Fifth choice:

$x=t+1$

$y=t^2+4t$

Step-by-step explanation:

Let's look at choice 1.

$x=t+1$

$y=t^2+2t$

I'm going to subtract 1 on both sides for the first equation giving me $x-1=t$ . I will replace the $t$ in the second equation with this substitution from equation 1.

$y=(x-1)^2+2(x-1)$

Expand using the distributive property and the identity $(u+v)^2=u^2+2uv+v^2$ :

$y=(x^2-2x+1)+(2x-2)$

$y=x^2+(-2x+2x)+(1-2)$

$y=x^2+0+-1$

$y=x^2$

So this not the desired result.

Let's look at choice 2.

$x=2t$

$y=4t^2+4t-3$

Solve the first equation for $t$ by dividing both sides by 2:

$t=\frac{x}{2}$ .

Let's plug this into equation 2:

$y=4(\frac{x}{2})^2+4(\frac{x}{2})-3$

$y=4(\frac{x^2}{4})+2x-3$

$y=x^2+2x-3$

This is the desired result.

Choice 3:

$x=t-3$

$y=t^2+2t$

Solve the first equation for $t$ by adding 3 on both sides:

$x+3=t$ .

Plug into second equation:

$y=(x+3)^2+2(x+3)$

Expanding using the distributive property and the earlier identity mentioned to expand the binomial square:

$y=(x^2+6x+9)+(2x+6)$

$y=(x^2)+(6x+2x)+(9+6)$

$y=x^2+8x+15$

Not the desired result.

Choice 4:

$x=t^2$

$y=2t-3$

I'm going to solve the bottom equation for $t$ since I don't want to deal with square roots.

Add 3 on both sides:

$y+3=2t$

Divide both sides by 2:

$\frac{y+3}{2}=t$

Plug into equation 1:

$x=(\frac{y+3}{2})^2$

This is not the desired result because the $y$ variable will be squared now instead of the $x$ variable.

Choice 5:

$x=t+1$

$y=t^2+4t$

Solve the first equation for $t$ by subtracting 1 on both sides:

$x-1=t$ .

Plug into equation 2:

$y=(x-1)^2+4(x-1)$

Distribute and use the binomial square identity used earlier:

$y=(x^2-2x+1)+(4x-4)$

$y=(x^2)+(-2x+4x)+(1-4)$

$y=x^2+2x+-3$

$y=x^2+2x-3$ .

This is the desired result.

3 0

3 years ago

Read 2 more answers

If the city bus through Austin travels at 40 miles per hour, how many miles

Neko [114]

It will travel 180 miles

4.5 • 40= 180

7 0

3 years ago

Explain how you would use integer tiles to find the quotient of -15 and 3

dsp73

-5 is the answer I believe

6 0

3 years ago

Read 2 more answers

Help! Sorry if it’s hard to see it would not look different everytime I retook the picture! :)

pshichka [43]

Answer:

d = 11.401754

For:
(X1, Y1) = (5, 4)
(X2, Y2) = (-4, -3)

Distance Equation Solution:

=√ (-4−5)2+(−3−4)2

=√ (-9)2+(−7)2

=√ 81+49

=√ 130

=11.401754

5 0

3 years ago