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RSB [31]
3 years ago
15

Need help with mean , median , mode question + a few more..

Mathematics
1 answer:
Andreas93 [3]3 years ago
3 0

Answer:

Mean:

a) 4

b) 2

c) 2

d) 2

Median:

a) 4,2

b) 5,2

c) 5,1

d) 4,1

Mode:

a) 1

b) 1

c) 1

d) 1

Step-by-step explanation:

Mean:

a) 1+4+2+1 = 8/4=4

b)1+5+2+1 = 9/4= 2.25 (round to the nearest whole number = 2)

c) 1+5+1+0 = 7/4 = 1.75 (round to the nearest whole number = 2)

d) 1+4+1+0 = 6/4 = 1.5 (round to the nearest whole number = 2)

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Find the area of the figure.
victus00 [196]

Answer:384cm²

Step-by-step explanation:

first find the area of the parallelogram

bh

b=24

h=7.5

24×7.5=180

second find the area of a rectangle

lw

l=24

w=8.5

24×8.5=204

add the areas together

204+180=384cm²

4 0
2 years ago
Using flowcharts, programmers can break large systems into subsystems that are easier to understand and code.
Temka [501]

It is True that Using flowcharts, programmers can break large systems into subsystems that are easier to understand and code.

<h3>What is the use of flowcharts?</h3>

A flowchart  serves a picture  consisting the separate steps of a process which is in sequential order and can be used to  break large systems into subsystems during programing.

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2 years ago
Mason used distributive property of multiplication to help him solve the equation 3 x 7 = ________. Mason did not get the same a
VikaD [51]

Answer:

Step-by-step explanation:

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6 0
2 years ago
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3 years ago
Add and Subtract Rational Expressions with a Common Denominator
Sladkaya [172]

Answer:

\displaystyle \frac{4q^2-q+3}{q^2+6q+5}-\frac{3q^2-q-6}{q^2+6q+5}=\frac{q^2+9}{q^2+6q+5}

Step-by-step explanation:

<u>Simplifying Rational Expressions</u>

If two or more rational expressions have the same denominator, the add and subtract operations are done only with the numerator. The final denominator will be the common of both.

The expression is:

\displaystyle \frac{4q^2-q+3}{q^2+6q+5}-\frac{3q^2-q-6}{q^2+6q+5}

Operating on the numerators:

\displaystyle \frac{4q^2-q+3}{q^2+6q+5}-\frac{3q^2-q-6}{q^2+6q+5}=\frac{4q^2-q+3-(3q^2-q-6)}{q^2+6q+5}

Removing parentheses:

\displaystyle \frac{4q^2-q+3}{q^2+6q+5}-\frac{3q^2-q-6}{q^2+6q+5}=\frac{4q^2-q+3-3q^2+q+6}{q^2+6q+5}

Simplifying:

\boxed{\displaystyle \frac{4q^2-q+3}{q^2+6q+5}-\frac{3q^2-q-6}{q^2+6q+5}=\frac{q^2+9}{q^2+6q+5}}

The expression cannot be further simplified.

7 0
2 years ago
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