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denpristay [2]
3 years ago
8

Plz give me correct answers ​

Mathematics
1 answer:
TEA [102]3 years ago
3 0
(1) 30,489.3 repeating
(2) 70,282
(3) 50,505
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Pleas please answer correctly !!!!!!!! Will mark brainliest !!!!!!!!!!!!
KiRa [710]

Answer:

10/9

Step-by-step explanation:

average rate of change in 0≤x≤9

=(3-(-7))/(9-0)=10/9

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3 years ago
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A farmer has 50 acres of corn crops. He harvested 3 acres of his crops in one afternoon. What is the decimal that represents the
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I NEED HELP PLS THIS IS DUE IN 3 HOURS
Mariulka [41]

Answer:

Part 1)  x^{2} -2x-2=(x-1-\sqrt{3})(x-1+\sqrt{3})

Part 2)  x^{2} -6x+4=(x-3-\sqrt{5})(x-3+\sqrt{5})

Step-by-step explanation:

we know that

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

Part 1)

in this problem we have

x^{2} -2x-2=0

so

a=1\\b=-2\\c=-2

substitute in the formula

x=\frac{-(-2)(+/-)\sqrt{-2^{2}-4(1)(-2)}} {2(1)}\\\\x=\frac{2(+/-)\sqrt{12}} {2}\\\\x=\frac{2(+/-)2\sqrt{3}} {2}\\\\x_1=\frac{2(+)2\sqrt{3}} {2}=1+\sqrt{3}\\\\x_2=\frac{2(-)2\sqrt{3}} {2}=1-\sqrt{3}

therefore

x^{2} -2x-2=(x-(1+\sqrt{3}))(x-(1-\sqrt{3}))

x^{2} -2x-2=(x-1-\sqrt{3})(x-1+\sqrt{3})

Part 2)

in this problem we have

x^{2} -6x+4=0

so

a=1\\b=-6\\c=4

substitute in the formula

x=\frac{-(-6)(+/-)\sqrt{-6^{2}-4(1)(4)}} {2(1)}

x=\frac{6(+/-)\sqrt{20}} {2}

x=\frac{6(+/-)2\sqrt{5}} {2}

x_1=\frac{6(+)2\sqrt{5}}{2}=3+\sqrt{5}

x_2=\frac{6(-)2\sqrt{5}}{2}=3-\sqrt{5}

therefore

x^{2} -6x+4=(x-(3+\sqrt{5}))(x-(3-\sqrt{5}))

x^{2} -6x+4=(x-3-\sqrt{5})(x-3+\sqrt{5})

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luda_lava [24]

Answer:

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Step-by-step explanation:

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The answer is 0.53 blocks by 5s. 
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