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netineya [11]
3 years ago
14

A farmer has a rectangular plot of land. There is a bother identical plot of land 100 yards east and 100 yards north. Find the c

ombined area of the two plots of land
Mathematics
1 answer:
Anna [14]3 years ago
8 0

Answer:

Step-by-step explanation:

Area of a rectangular plot = Length × width

With the aid of the diagram attached below.

<u>For plot 1:</u>

The area = ( 60 - 20 ) × ( 80 - 20 )

Area = 40 × 60

Area = 2400 sq yard

<u>For plot 2:</u>

Area = (160 - 120 ) × ( 180 - 120 )

Area = 40 × 60

Area = 2400 sq yard

Therefore, the combined area of the two plots of land = 2400 + 2400

= 4800 square yards

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It’s not B can someone plz help me with this it will be appreciated I’m really confused
Viktor [21]

Answer:

83.4

Step-by-step explanation:

Area of a Regular Polygon: L (of side) times apothem (height) x 1/2

L : 13.9

Looking at the triangle we can assume the height would be 12 since its logical that 3 of the 4 lines can fit in the middle of the triangle.

H: 12

13.9 x 12 = 166.8

166.8/2 = 83.4

3 0
3 years ago
If it's $8 for four bottles how much is each bottle?
cluponka [151]
Hi there! $8 per 4 bottles means price/# of bottles will give you the average price per bottle.

8/4=$2

Therefore it is $2 for 1 bottle.

Hope this helps!
5 0
3 years ago
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How to solve Which ordered pair is a solution for x − 3y = 1?
babunello [35]
There is no one answer (ordered pair) to this equation and the answer is found by graphing or trying out different values for each variable. Anyway, here are some solutions; (1,0), (4,1), (0,-1/3).
5 0
3 years ago
13. What is the rule of the function whose<br> graph is shown below?
PtichkaEL [24]

Answer:

x-x-y

Step-by-step explanation:

5 0
3 years ago
A rectangular box without a lid is to be made from 48 m2 of cardboard. Find the maximum volume of such a box. SOLUTION We let x,
tatiyna

Answer:

The maximum volume of such box is 32m^3

V = x×y×z = 32 m^3

Step-by-step explanation:

Given;

Total surface area S = 48m^2

Volume of a rectangular box V = length×width×height

V = xyz ......1

Total surface area of a rectangular box without a lid is

S = xy + 2xz + 2yz = 48 .....2

To be able to maximize the volume, we need to reduce the number of variables.

Let assume the rectangular box has a square base,that means; length = width

x = y

Substituting y with x in equation 1 and 2;

V = x^2(z) ....3

x^2 + 4xz = 48 .....4

Making z the subject of formula in equation 4

4xz = 48 - x^2

z = (48 - x^2)/4x .......5

To be able to maximize V, we need to reduce the number of variables to 1, by substituting equation 5 into equation 3

V = x^2 × (48 - x^2)/4x

V = (48x - x^3)/4

differentiating V with respect to x;

V' = (48 - 3x^2)/4

At the maximum point V' = 0

V' = (48 - 3x^2)/4 = 0

Solving for x;

3x^2 = 48

x = √(48/3)

x = √(16)

x = 4

Since x = y

y = 4

From equation 5;

z = (48 - x^2)/4x

z = (48 - 4^2)/4(4)

z = 32/16

z = 2

The maximum volume can be derived by substituting x,y,z into equation 1;

V = xyz = 4×4×2 = 32 m^3

7 0
4 years ago
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