Given :
Abraham has visited 10 countries already. He has a goal of visiting at least 50 countries.
He plans to achieve this goal by visiting 5 new countries per year (y) for the next several years.
To Find :
Which inequality and solution shows the amount of years that it will take for Abraham to meet his goal.
Solution :
Let, after x years Abraham visited y countries.
It is mathematically given as :
Now, it is given that his goal is minimum of 50 countries.
So,
Therefore, minimum years required to meet his goals are 8.
Hence, this is the required solution.
Answer:
answer is -7/2
Step-by-step explanation:
The linear equation that has a slope of -7 and crosses the x-axis at (3, 0) is:
y = -7x + 21
<h3>
How to find the linear equation?</h3>
A general linear equation is:
y = a*x +b
Where a is the slope and b is the y-intercept.
The slope must be equal to the limit found in part a, and you say that it is equal to -7, so the slope is -7. And for how is written the problem, I understand that it crosses the x-axis at x = 3.
Then we will have:
y = -7*x + b
Such that, when x = 3, y = 0, then:
0 = -7*3 + b
21 = b
Then the linear equation is y = -7x + 21
If you want to learn more about linear equations:
brainly.com/question/1884491
#SPJ1
Answer:
x=10 n=18.5 s=6
Step-by-step explanation:
4x-10=30
Add 10 to both sides
4x-10+10=30+10
4x=40
Divide by 4 on both sides
(4x)/4=40/4
x=10
2n-7=30
Add 7 to both sides
2n-7+7=30+7
2n=37
Divide by 2 on both sides
(2n)/2=37/2
n=18.5
(s/3)+2=4
Subtract 2 from both sides
(s/3)+2-2=4-2
(s/3)=2
Multiply by 3 on both sides
3s/3=2*3
s=6
Step-by-step explanation:
cho f(t)=(t-4)u(t-2)phep bien doi laplace la
F(s)=e^-2s/s^2-2e^-2s/s62
