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3 years ago

14

You are using a recipe for meatloaf that calls for 10 ounces of ground beef: the recipe is for 5 servings but you want to make e

nough for 8. How much ground beef should you use?

1 answer:

pogonyaev3 years ago

8 0

<u><em>Answer:</em></u>

<u><em>16</em></u>

<u><em>Step-by-step explanation:</em></u>

<u><em>10 divided by 5 equals 2 (10/5=2)</em></u>

<u><em>2 times 8 equals 16 (2 x 8 = 16)</em></u>

<u><em></em></u>

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Let L be the line with parametric equations x=5+t,y=6,z=−2−3t. Find the vector equation for a line that passes through the point

scZoUnD [109]

Answer:

The required equations are

$(-5 \hat i + 7 \hat j + 8 \hat k )+\lambda \left((10+\frac {3}{\sqrt {10}})\hat i -\hat j +(6- \frac {9}{\sqrt {10}})\hat k\right)=0$ and

$(-5 \hat i + 7 \hat j + 8 \hat k )+\lambda \left((10-\frac {3}{\sqrt {10}})\hat i -\hat j +(6+ \frac {9}{\sqrt {10}})\hat k\right)=0$ .

Step-by-step explanation:

The given parametric equation of the line, $L$ , is $x=5+t, y=6, z=-2-3t,$ so, an arbitrary point on the line is $R(x,y,z)=R(5+t, 6, -2-3t)$

The vector equation of the line passing through the points $P(-5,7,-8)$ and $R(5+t, 6, -2-3t)$ is

$\vec P + \lambda \vec{(PR)}=0$

$\Rightarrow (-5 \hat i + 7 \hat j - 8 \hat k )+\lambda \left((5+t-(-5))\hat i + (6-7)\hat j +(-2-3t-8)\hat k\right)=0$

$\Rightarrow (-5 \hat i + 7 \hat j - 8 \hat k )+\lambda \left((10+t)\hat i -\hat j +(6-3t)\hat k\right)=0\;\cdots (i)$

The given equation can also be written as

$\frac {x-5}{1}=\frac {v-6}{0}=\frac{z+2}{-3}=t \; \cdots (ii)$

The standard equation of the line passes through the point $P_0(x_0,y_0,z_0)$ and having direction $\vec v= a_1 \hat i +a_2 \hat j +a_3 \hat k$ is

$\frac {x-x_0}{a_1}=\frac {y-y_0}{a_2}=\frac{z-z_0}{a_3}=t \;\cdots (iii)$

Here, The value of the parameter, $t$ , of any point $R$ at a distance $d$ from the point, $P_0$ , can be determined by

$|t \vec v|=d\;\cdots (iv)$

Comparing equations $(ii)$ and $(iii)$

The line is passing through the point $P_0 (5,6,-2)$ having direction $\vec v=\hat i -3 \hat k$ .

Note that the point $Q(5,6,-2)$ is the same as $P_0$ obtained above.

Now, the value of the parameter, $t$ , for point $R$ at distance $d=3$ from the point $Q(5,6,-2)$ can be determined by equation $(iv)$ , we have

$|t(\hat i -3 \hat k)|=3$

$\Rightarrow t^2|(\hat i -3 \hat k)|^2=9$

$\Rightarrow 10t^2=9$

$\Rightarrow t^2=\frac {9}{10}$

$\Rightarrow t=\pm \frac {3}{\sqrt {10}}$

Put the value of $t$ in equation $(i)$ , the required equations are as follows:

For $t= \frac {3}{\sqrt {10}}$

$(-5 \hat i + 7 \hat j - 8 \hat k )+\lambda \left((10+\frac {3}{\sqrt {10}})\hat i -\hat j +\left(6-3\times \frac {3}{\sqrt {10}})\hat k\right)=0$

$\Rightarrow (-5 \hat i + 7 \hat j - 8 \hat k )+\lambda \left((10+\frac {3}{\sqrt {10}})\hat i -\hat j +(6- \frac {9}{\sqrt {10}})\hat k\right)=0$

and for $t= -\frac {3}{\sqrt {10}}$ ,

$(-5 \hat i + 7 \hat j - 8 \hat k )+\lambda \left((10+\left (-\frac {3}{\sqrt {10}}\right))\hat i -\hat j +(6-3\times \left(-\frac {3}{\sqrt {10}}\right)\hat k\right)=0$

$\Rightarrow (-5 \hat i + 7 \hat j - 8 \hat k )+\lambda \left((10-\frac {3}{\sqrt {10}})\hat i -\hat j +(6+ \frac {9}{\sqrt {10}})\hat k\right)=0$

8 0

3 years ago

In still water Kevin and Virginia can paddle a canoe at 12mph.It takes them a total of 6hours to paddle 32 miles up a river and

denpristay [2]

Let c represent the speed of the current.

time = distance/speed

Upriver, the current is subtracted from the canoe speed; downriver, it adds.
6 = 32/(12 -c) +32/(12 +c)
6(12² -c²) = 32(12 +c) +32(12 -c) . . . . . multiply by (12 +c)(12 -c)
0 = 6c² -96 . . . . . . . . . . . . . . . . . . . . . . subtract the left side
96/6 = c² . . . . . . . . . . . . . . . . . . . . . . . . add 96, divide by 6
4 = c . . . . . . . . . . . . . . . . . . . . . . . . . . . . take the square root

The rate of the current is 4 mph.

4 0

3 years ago

How can systems of equations be used to represent situations and solve problems?

uysha [10]

Answer:

To solve real world problems, we can use the relationship between the quantities and form equations which represent the situation given in the problem. Then, we can use these equations to solve the problems.

Step-by-step explanation:

4 0

2 years ago

Manuel borrowed $1,500 from his bank and signed a

Mice21 [21]

Answer:

The total interest to pay back on the loan is $122.40

Step-by-step explanation:

Here. we want to get the amount of interest on the loan

We are going to use the compound interest formula here

A = P(1 + r/n)^nt

where A is the amount to be paid back

P is the amount borrowed called the principal which is $1,500

r is the interest rate which is 4% annually

This is same as 4/100 = 0.04

n is the number of times the interest will be compounded per year ; annually means yearly and so for this case, n = 1

t is the number of years = 2

So we have;

A = 1500(1 + 0.04/1)^(2)(1)

A = 1500(1.04)^(2)

A =$ 1,622.40

So the amount of interest is the difference between the amount borrowed and the value to pay back

That will be;

$1,622.40 - $1,500

= $122.40

3 0

2 years ago

6 7 8 only 8th grade math

saul85 [17]

☺ I might have misunderstood, but I can help if you give me the question. ☺

8 0

2 years ago