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Lynna [10]
3 years ago
8

The distance of planet Saturn from the Sun is 1.5 ⋅ 109 kilometers, and the distance of planet Venus from the Sun is 1.1 ⋅ 108 k

ilometers. About how many more kilometers is the distance of Saturn from the Sun than the distance of Venus from the Sun? A 0.4 • 10^8. B 0.4 •10^9. C 1.4 • 10^9. D 1.4 • 10^10
Mathematics
1 answer:
Kobotan [32]3 years ago
8 0

the distance is s mil lion

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increase in x results in the decrease in y

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Find the ratio of the following to its lowest term with whole solution
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Hey, we just need to find the gcf for them.

A) 3:4
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3 years ago
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A professor finds that the average SAT score among all students attending his college is 1150 ± 150 (μ ± σ). He polls his class
solniwko [45]

Answer:

Step-by-step explanation

Hello!

Be X: SAT scores of students attending college.

The population mean is μ= 1150 and the standard deviation σ= 150

The teacher takes a sample of 25 students of his class, the resulting sample mean is 1200.

If the professor wants to test if the average SAT score is, as reported, 1150, the statistic hypotheses are:

H₀: μ = 1150

H₁: μ ≠ 1150

α: 0.05

Z= \frac{X[bar]-Mu}{\frac{Sigma}{\sqrt{n} } } ~~N(0;1)

Z_{H_0}= \frac{1200-1150}{\frac{150}{\sqrt{25} } } = 1.67

The p-value for this test is  0.0949

Since the p-value is greater than the level of significance, the decision is to reject the null hypothesis. Then using a significance level of 5%, there is enough evidence to reject the null hypothesis, then the average SAT score of the college students is not 1150.

I hope it helps!

7 0
3 years ago
6th grade math help me pleaseee
creativ13 [48]

Answer:

B and D

Step-by-step explanation:

First off, we can rotate it. When rotating, I found that the x and y values switch places in a way.

We would need to rotate it 90 degrees counterclockwise about the origin in order to get it in the same position as triangle BDE. This makes statement B correct.

In order to make triangle ABC smaller, the dilation would have to be smaller than one. Counting the right side's length, ABC has 6 squares and BDE has 3.

This would mean 6 * 1/2 = 3, meaning statement D is true.

6 0
3 years ago
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4/x-1+6/x+1=-12/x^2-1
Mademuasel [1]
\frac{4}{x - 1} + \frac{6}{x + 1} = \frac{-12}{x^{2} - 1}

\frac{4(x + 1)}{(x - 1)(x + 1)} + \frac{6(x - 1)}{(x - 1)(x + 1)} = \frac{-12}{x^{2} - 1}

\frac{4x + 4}{x^{2} - 1} + \frac{6x - 6}{x^{2} - 1} = \frac{-12}{x^{2} - 1}

\frac{10x - 2}{x^{2} - 1} = \frac{-12}{x^{2} - 1}

(10x - 2)(x^{2} - 1) = -12(x^{2} - 1)
10x^{3} - 10x^{2} - 2x^{2} + 2 = -12(x^{2}) + 12(1)
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\frac{10x^{3}}{10} = \frac{10}{10}

x^{3} = 1
x = 1
4 0
3 years ago
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