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Harrizon [31]
3 years ago
15

Which set of line segments can be used to construct a triangle? A) 2 cm, 8 cm, and 9 cm B) 3 cm, 6 cm, and 2 cm C) 5 cm, 9 cm, a

nd 3 cm D) 6 cm, 3 cm, and 10 cm
Mathematics
2 answers:
Alik [6]3 years ago
8 0

Answer:It’s not A, I got it wrong it’s B 3cm, 3cm, and 2cm.

Step-by-step explanation:

zheka24 [161]3 years ago
3 0

Answer: option A is the correct answer

Step-by-step explanation:

The set of line segments that can be used is the one such that, its longest side is lesser than the semi perimeter,s[s=(a+b+c)/2] of the triangle.

If we apply this condition on the given line segments,

A) 2 cm, 8 cm, and 9 cm

s = (2+8+9)/2 = 9.5

9.5 is greater than 9cm

B) 3 cm, 6 cm, and 2 cm

s = (3+6+2)/2= 5.5

5.5 is lesser than 6. If we go on to look for the area using

Area = √s(s-a)(s-b)(s-c), it would be impossible because we would end up having square root of a negative number.

C) 5 cm, 9 cm, and 3 cm

s = (5+9+3)/2 = 8.5

8.5 is lesser than 9cm

If we go on to look for the area using

Area = √s(s-a)(s-b)(s-c), it would be impossible because we would end up having square root of a negative number.

D) 6 cm, 3 cm, and 10 cm

s = (6+3+10)/2 = 9.5

9.5 is lesser than 10

If we go on to look for the area using

Area = √s(s-a)(s-b)(s-c), it would be impossible because we would end up having square root of a negative number.

So option A is the correct answer

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Describe in words where the square root of 50 minus 10 would be plotted on a number line.
Dafna1 [17]

The required value lies Between 6 and 7, but closer to 6. Option C is correct.

Given that,
The square root of 50 minus 10 would be plotted on a number line.

<h3>What is a number line?</h3>

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If <img src="https://tex.z-dn.net/?f=f%28x%29%3D%20%5Cfrac%7B1%7D%7Bx-2%7D%20" id="TexFormula1" title="f(x)= \frac{1}{x-2} " alt
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We have:
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g(x)
Then:
(fg)(x)=[1/(x-2)](g(x))=g(x)/(x-2)
Now; we calculate: (fg)`(x)
Remember: (u/v)=(u`v-vu´)/v²
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(fg)´(x)=[g´(x)*(x-2) - 1*g(x)]/ (x-2)²
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