Answer: (2p + 1.5d) + (5*(2)) = T
Step-by-step explanation: (2p + 1.5d) + (5*(2)) = T
Since there are no costs, i'll make up my own uwu;
Matinee = $5
Popcorn = $2
Drink = $1.5
T = total
(2p + 1.5d) + (5*(2)) = T
2p ($2 for each bag of popcorn - p represents popcorn)
1.5d ($1.5 for each drink, - d represents drinks)
5*2 ( 5 * 2 because we are already given the amount of matinee tickets they buy.
The answer is 350.
<em>
m= minutes</em>
Plan 1: 9+0.13<em>m</em>
Plan 2: 23+0.09<em>m</em>
9+0.13<em>m</em> = 23+0.09<em>m</em>
-9 -9
0.13<em>m</em> = 14+0.09<em>m</em>
-0.09<em>m</em> -0.09<em>m</em>
0.04<em>m</em>= 14
14÷0.04= 350
<em>m</em>= 350
The car would be worth $16,000 after 5 years.
Answer:
D
Step-by-step explanation:
Answer:
The likelihood that the professor's socks matched his pants on both days is 0.5625
Step-by-step explanation:
Total no. of pair of socks = 24
No. of black pairs = 18
We are given that he selects one pair of socks on Monday and one on Tuesday. Since he has lots of clean socks in the drawer he does not do laundry.
So, It is a case of replacement
He always wears black pants.
We are supposed to find he likelihood that the professor's socks matched his pants on both days i.e. Black socks both days.
So ,Probability of wearing black socks on Monday = 
So ,Probability of wearing black socks on Tuesday =
So,the likelihood that the professor's socks matched his pants on both days = 
Hence the likelihood that the professor's socks matched his pants on both days is 0.5625