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2 years ago

13

Find out about tall buildings where you live. What is the tallest building in your hometown or state? What is the difference in

height between this building and the Taipei 101 building that is 1,667 feet tall?

1 answer:

Aleks04 [339]2 years ago

6 0

The tallest building in my area is the reunion tower which is 562 ft and the difference is 1106

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lara31 [8.8K]

The total annual returns on each of the following investments would be 65 times 11,300 and the answer you’ll get divide by 2

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2 years ago

A pet toy manufacturer is designing a plastic ball for dogs that will float in water. In order for the ball to float it must hav

algol13

Answer:

3.576 cm

Step-by-step explanation:

radius of ball, r=?

Given:

Density, p = 0.600g/mL

mass, m= 115g

finding volume, v of ball by using formula p=m/v

v= m/p

= 115/0.600

=191.666 mL^3

=191.666 cm^3

Now using formula v= (4/3)πr^3 to find radius, r of the ball

r^3= 3v/4π

= 3(191.666)/4π

=45.75 cm

r =3.5767 cm !

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3 years ago

Number of emails received in one account every day from the day it was created until it was canceled:

3241004551 [841]

The answer is B. Complete information.

A sample means only part of the whole. From the day the email was created till it was cancelled is the whole population. Consider that no mails will no longer go in because it is closed so no more additional information or data will enter that category. So it would be considered as complete. If the situation were to ask from one point to another before it was cancelled it would be considered as a sample.

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2 years ago

Find the area each sector. Do Not round. Part 1. NO LINKS!!<br><br>

sladkih [1.3K]

Answer:

$\textsf{Area of a sector (angle in degrees)}=\dfrac{\theta}{360 \textdegree}\pi r^2$

$\textsf{Area of a sector (angle in radians)}=\dfrac12r^2\theta$

17) Given:

$\theta$ = 240°
r = 16 ft

$\textsf{Area of a sector}=\dfrac{240}{360}\pi \cdot 16^2=\dfrac{512}{3}\pi \textsf{ ft}^2$

19) Given:

$\theta=\dfrac{3 \pi}{2}$
r = 14 cm

$\textsf{Area of a sector}=\dfrac12\cdot14^2 \cdot \dfrac{3\pi}{2}=147 \pi \textsf{ cm}^2$

21) Given:

$\theta=\dfrac{ \pi}{2}$
r = 10 mi

$\textsf{Area of a sector}=\dfrac12\cdot10^2 \cdot \dfrac{\pi}{2}=25 \pi \textsf{ mi}^2$

23) Given:

$\theta$ = 60°
r = 7 km

$\textsf{Area of a sector}=\dfrac{60}{360}\pi \cdot 7^2=\dfrac{49}{6}\pi \textsf{ km}^2$

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2 years ago

The second step in solving problems using order of operations is solving the

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PEMDAS.....parenthesis, exponents, multiplication/division, addition/subtraction

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2 years ago

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