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Delvig [45]
3 years ago
7

The angle measurements in the diagram are represented by the following expressions.

Mathematics
1 answer:
gladu [14]3 years ago
3 0

Answer:

                             

Step-by-step explanation:


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Factor the polynomial.<br><br> X2-13x+30
Svetllana [295]

Answer:

<h2>\ \boxed{(x - 3)(x - 10)}</h2>

Step-by-step explanation:

{x}^{2}  - 13x  + 30

Write -13x as a difference

{x}^{2}  - 3x - 10x + 30

Factor out x from the expression

x(x - 3) - 10x + 30

Factor out -10 from the expression

x(x - 3) - 10(x - 3)

Factor out x-3 from the expression

(x - 3)(x - 10)

Hope I helped!

Best regards!!

4 0
3 years ago
Find the standard form of the equation of the parabola with a vertex at the origin and a focus at (0, 9). I need help
Juliette [100K]
From the given data:<span> vertex at the origin and a focus at (0, 9), the parabola should be facing upwards. In this case, the length of the latus rectum is 9 units which is a. Hence the equation becomes y = 4 (9) x^2. The equation is equal to y = 36 x^2. The standard form is 36 x^2 - y = 0.</span>
3 0
3 years ago
Please help its pretty easy
aleksandrvk [35]

Answer:

26/36 numbers are greater than 10

Simplify

13/18

Multiply by the chance of getting tails

13/18 x 1/2 = 13/36

13/36 your answer

26 wanted numbers / 36 amount of numbers

1 tails / 2 sides

Step-by-step explanation:

5 0
2 years ago
Help! giving brainlest to best answer!​
Pani-rosa [81]

Answer:

C...........................

3 0
2 years ago
Find the area of the shaded region.f(x)=4x+3x2−x3,g(x)=0<br> The area is _____.
Tasya [4]

Answer:

The answer is " \bold{\frac{7}{2}}"

Step-by-step explanation:

Given value:

\to f(x)=4x+3x^2-x^3\\\\\to g(x)=0

Find:

area=?

calculation:

\ Area = \int_{-1}^{0} -(4x+3x^2-x^3) dx  + \int_{0}^{1} (4x+3x^2-x^3) dx  \\\\

        =  -(2x^2+x^3- \frac{x^4}{4})_{-1}^{0} + (2x^2+x^3- \frac{x^4}{4})_{0}^{1}\\\\\\=  -( 2x^2+x^3- \frac{x^4}{4})_{-1}^{0} + (2x^2+x^3- \frac{x^4}{4})_{0}^{1}\\\\\\= ( 2- 1 -\frac{1}{4}) + (2+1- \frac{1}{4})\\\\\\=  ( \frac{8-4-1}{4}) + (\frac{8+4-1}{4})\\\\=  ( \frac{3}{4}) + (\frac{11}{4})\\\\=   \frac{3}{4} + \frac{11}{4}\\\\= \frac{11+3}{4}\\\\= \frac{14}{4}\\\\= \frac{7}{2}\\\\

7 0
3 years ago
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