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DochEvi [55]
3 years ago
9

A student tries out for the track team and runs a lap in 45 seconds. The coach tells her she will have to cut her time by 50% to

make the team. How fast must she run a lap to make the team?
Mathematics
2 answers:
Fiesta28 [93]3 years ago
8 0
Cutting her time by 50% means reducing her time by half. Half of 45 seconds is 22.5 seconds. Therefore, to make the team, she must run a lap in 22.5 seconds.
Scrat [10]3 years ago
5 0

Answer:

Cutting her time by 50% means reducing her time by half. Half of 45 seconds is 22.5 seconds. Therefore, to make the team, she must run a lap in 22.5 seconds.

Step-by-step explanation:

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Step-by-step explanation:

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Let <span>simplify the equations a^7xy-a^6y-a^5x=a^4(b^4-1) and (a^mx-a^n)(a^py-a^2)=a^4b^4:
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<span>1) a^7xy-a^6y-a^5x+a^4=a^4b^4
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<span>and
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<span>2) a^{m+p}xy-a^{n+p}y-a^{m+2}x+a^{n+2}=a^4b^4.
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Then n=2 \\ p=4 \\ m=3 and mnp=24.
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Step-by-step explanation:

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Step-by-step explanation:

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