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3 years ago

What is the range of the function f(x) =4x-1 when the domain is -3 ,0,4 ?

Mathematics

1 answer:

dedylja [7]3 years ago

3 0

Answer:

The range of this function is {-13, -1, 15}.

Step-by-step explanation:

Evaluate f(x) = 4x - 1 at {-3, 0, 4}:

f(-3) = -13

f(0) = -1

f(4) = 15

The range of this function is {-13, -1, 15}.

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Evaluate (c − b)2 + a2 for a = –5, b = –2, and c = –4.

taurus [48]

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(-4 - (-2))² + (-5)²

(-4 + 2)² + (-5)²

(-2)² + (-5)²

4 + 25

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3 years ago

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Lina20 [59]

ANSWER:
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2 years ago

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Colt1911 [192]

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3 years ago

8x + 3(2 - x) = 5x + 6

tino4ka555 [31]

Answer:

0=0

Step-by-step explanation:

distribute

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6 0

3 years ago

Let u = <-9, 4>, v = <8, -5>. Find u - v. <br> URGENT

Pie

To subtract vectors, you simply have to subtract correspondent coordinates.

So, if you have

$u = \langle u_1,\ u_2,\ldots u_n\rangle ,\quad v = \langle v_1,\ v_2,\ldots v_n\rangle$

the subtraction is simply

$u-v = \langle u_1-v_1,\ u_2-v_2,\ldots u_n-v_n\rangle$

So, in your case, we have

$\langle-9,4\rangle-\langle 8,-5\rangle=\langle -9-8, 4+5\rangle=\langle -17,9\rangle$

3 0

3 years ago