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rosijanka [135]
3 years ago
9

What is the domain of g

Mathematics
1 answer:
Yuki888 [10]3 years ago
8 0

Look at the picture.

Domain -7 ≤ t ≤ 7

Range -9 ≤ y ≤ 9

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Find the length of the third side. If necessary, round to the nearest tenth.<br> 17<br> 15
xenn [34]

Answer:

8

Step-by-step explanation:

Use the pythagorean theorem.

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3 years ago
Pls answer ASAP........
Brums [2.3K]

Answer: 1/3

Step-by-step explanation:

their there choices he can only choice one

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3 years ago
The angles of a quadrilateral are represented by 9x, (20x + 16) (12x + 10), and (7x- 2)°. What is the value of x?
Pepsi [2]

Answer:

x=7

Step-by-step explanation:

9x+20x+16+12x+10+7x-2=360

48x+24=360

48x=360-24

48 x=336

x=336/48=7

5 0
2 years ago
Simplify the expression. 34 • 3
bekas [8.4K]

Answer:

102

Step-by-step explanation:

34*3=102

the dot in the middle is just another way to say that it is multiplying the equation so it just mean that your are multiplying 34 by 3 which is 102

3 0
3 years ago
A random variable x follows a normal distribution with mean d and standard deviation o=2. It is known that x is less than 5 abou
Vaselesa [24]

Answer:

The mean of this distribution is approximately 3.96.

Step-by-step explanation:

Here's how to solve this problem using a normal distribution table.

Let z be the

\displaystyle z = \frac{x - \mu}{\sigma}.

In this question, x = 5 and \sigma = 2. The equation becomes

\displaystyle z = \frac{5 - \mu}{2}.

To solve for \mu, the mean of this distribution, the only thing that needs to be found is the value of z. Since

The problem stated that P(X \le 5) = 69.85\% = 0.6985. Hence, P(Z \le z) = 0.6985.

The problem is that the normal distribution tables list only the value of P(0 \le Z \le z) for z \ge 0. To estimate  z from P(Z \le z) = 0.6985, it would be necessary to find the appropriate

Since P(Z \le z) = 0.6985 and is greater than P(Z \le 0) = 0.50, z > 0. As a result, P(Z \le z) can be written as the sum of P(Z < 0) and P(0 \le Z \le z). Besides, P(Z < 0) = P(Z \le 0) = 0.50. As a result:

\begin{aligned}&P(Z \le z)\\ &= P(Z < 0) + P(0 \le Z \le z) \\ &= 0.50 + P(0 \le Z \le z)\end{aligned}.

Therefore:

\begin{aligned}&P(0 \le Z \le z) \\ &= P(Z \le z) - 0.50 \\&= 0.6985 - 0.50 \\&=0.1985 \end{aligned}.

Lookup 0.1985 on a normal distribution table. The corresponding z-score is 0.52. (In other words, P(0 \le Z \le 0.52) = 0.1985.)

Given that

  • z = 0.52,
  • x =5, and
  • \sigma = 2,

Solve the equation \displaystyle z = \frac{x - \mu}{\sigma} for the mean, \mu:

\displaystyle 0.52 = \frac{5 - \mu}{2}.

\mu = 5 - 2 \times 0.52 = 3.96.

3 0
3 years ago
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