3 years ago

Could someone answer this for me please? Thank you!

Mathematics

1 answer:

katovenus [111]3 years ago

4 0

I hope this helps! The data they give you gives you coordinate points that will help you solve the problem!

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A number cube is rolled. What is the probability that the result is a number greater than 4?

JulijaS [17]

Answer:

1/3

Step-by-step explanation:

Number cube has 6 sides so a number greater than 4 is 5 and 6. Which is 2 times so 2/6 which can simplify to 1/3

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3 years ago

the area of rectangle a is 11/12 square meters. the area of rectangle b is 8/12 square meters. how much larger is rectangle a?

tresset_1 [31]

11 / 12 - 8 / 12 = 3 / 12 = 1/4 square meters;

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2 years ago

How do you know if something is congruent? (scale Factors)

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How would I find the integral of <img src="https://tex.z-dn.net/?f=%5Cint%5Cfrac%7Btdt%7D%7Bt%5E4%2B2%7D" id="TexFormula1" title

kotegsom [21]

Let $t=\sqrt y$ , so that $t^2=y$ , $t^4=y^2$ , and $\mathrm dt=\dfrac{\mathrm dy}{2\sqrt y}$ . Then

$\displaystyle\int\frac t{t^4+2}\,\mathrm dt=\int\frac{\sqrt y}{2\sqrt y(y^2+2)}\,\mathrm dy=\frac12\int\frac{\mathrm dy}{y^2+2}$

Now let $y=\sqrt2\tan z$ , so that $\mathrm dy=\sqrt2\sec^2z\,\mathrm dz$ . Then

$\displaystyle\frac12\int\frac{\mathrm dy}{y^2+2}=\frac12\int\frac{\sqrt2\sec^2z}{(\sqrt2\tan z)+2}\,\mathrm dz=\frac{\sqrt2}4\int\frac{\sec^2z}{\tan^2z+1}\,\mathrm dz=\frac1{2\sqrt2}\int\mathrm dz=\dfrac1{2\sqrt2}z+C$

Transform back to $y$ to get

$\dfrac1{2\sqrt2}\arctan\left(\dfrac y{\sqrt2}\right)+C$

and again to get back a result in terms of $t$ .

$\dfrac1{2\sqrt2}\arctan\left(\dfrac{t^2}{\sqrt2}\right)+C$

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3 years ago

How many ways are there to split 10 people into five pairs?<br> Pls give me answer fast!

alexandr402 [8]

Answer:

945 arrangements

Step-by-step explanation:

(fifth term in the sequence with m=5 and five pairs for 10 people in total).

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2 years ago